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Archy [21]
3 years ago
14

The box that holds a bouquet of roses is shaped like a rectangular prism.

Mathematics
2 answers:
FrozenT [24]3 years ago
6 0

Answer:

17 inches

Step-by-step explanation:

918=6*9*L

918=54*L

918/54=17inches length

Aleksandr [31]3 years ago
4 0

The Length of the box is 17 inches

Hope it helps

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What is the area of the regular hexagon?
myrzilka [38]

Answer:

216 \sqrt{3} \: {in}^{2}

Step-by-step explanation:

Area \: of \: regular \: hexagon \\  =  \frac{ 3 \sqrt{3} }{2}  {side}^{2}  \\ =  \frac{ 3 \sqrt{3} }{2}  \times  {12}^{2}  \\ =  \frac{ 3 \sqrt{3} }{2}  \times  144 \\ =  { 3 \sqrt{3} } \times  72 \\  = 216 \sqrt{3}  \:  {in}^{2}  \\

3 0
3 years ago
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Express each decimal as a fraction or mixed number in simplest form.<br><br><br><br> 9-4.
madam [21]

Answer:

5

Step-by-step explanation:

4 0
3 years ago
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If a x 10^n is scientific notation, then a must be between 1 and
Yanka [14]

Answer:

  A)  10

Step-by-step explanation:

In the US, a number in scientific notation will have a mantissa (a) such that ...

  1 ≤ a < 10

That is, the value of "a" must be between 1 and 10 (not including 10).

_____

<em>Comment on alternatives</em>

In other places or in particular applications (some computer programming languages), the standard form of the number may be a×10^n with ...

  0.1 ≤ a < 1

In engineering use, the form of the number is often chosen so that "n" is a multiple of 3, and "a" is in the range ...

  1 ≤ a < 1000

This makes it easier to identify and use the appropriate standard SI prefix: nano-, micro-, milli-, kilo-, mega-, giga-, and so on.

4 0
3 years ago
Suppose a teacher finds that the
SVETLANKA909090 [29]

Answer:

If a student with 2 absences got a score of 12, we can affirm that the student got 6 points for every absence she or he had.

Therefore, if a student had 3 absences and the results varied inversely with the number of absences they had, it means that her or his score would be: 3 * 6 = 18 points.

<u>The correct answer is 18 points.</u>

Step-by-step explanation:

4 0
3 years ago
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1/1×3 + 1/3×5 + ... + 1/47×49 HELP PLZ
Natalka [10]

Answer:

  24/49

Step-by-step explanation:

Let's add the terms and see if there's a pattern

  \dfrac{1}{1\times 3}+\dfrac{1}{3\times 5}=\dfrac{5+1}{1\times 3\times 5}=\dfrac{2}{5}\quad\text{sum of 2 terms}\\\\\dfrac{2}{5}+\dfrac{1}{5\times 7}=\dfrac{14+1}{5\times7}=\dfrac{3}{7}\quad\text{sum of 3 terms}

Suppose we say the sum of n terms is (n/(2n+1)), the next term in the series will be 1/((2n+1)(2n+3)) and adding that to the presumed sum gives ...

  \dfrac{n}{2n+1}+\dfrac{1}{(2n+1)(2n+3)}=\dfrac{n(2n+3)+1}{(2n+1)(2n+3)}=\dfrac{2n^2+3n+1}{(2n+1)(2n+3)}\\\\=\dfrac{(2n+1)(n+1)}{(2n+1)(2n+3)}=\dfrac{n+1}{2n+3}\text{ matches }\dfrac{(n+1)}{2(n+1)+1}

Then it appears the sum of n terms is (n/(2n+1)). So, the sum of 24 terms is ...

  S_{24}=\dfrac{24}{2\times24+1}=\boxed{\dfrac{24}{49}}

3 0
3 years ago
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