since we know the <u>common difference</u> is d is 6, then to get from the 6th term to the 10th term, we use d 4 more times.
6th term..................37
7th term...................37 + 6
8th term...................37 + 6 + 6
9th term...................37 + 6 + 6 + 6
10th term...................37 + 6 + 6 + 6 + 6
.....................................61.
We are given
number of heads =15
we know that
any healthy dragon has three heads
horse has 1 head
chicken has 1 head
Let's assume
number of dragons is x
number of horses is y
number of chickens is z
so, we will get
first equation:
number of legs =50
any healthy dragon has four legs
chicken has 2 legs
horse has four legs
so, we can get second equation as
we can simplify it
now, we can find third equation
dragon has two wings
horse has no wings
chicken has two wings
so, we will get third equations as
now, we can simplify it
so, we will get system of equations as
now, we can use substitution
We can find for z from third equation
we can plug this in first equation
now, we can solve for y
now, we can plug this z and y into second equation
now, we can solve for x
now, we can find y and z
we can plug x=1
we can plug x=1
Hence ,
number of dragons is 1
number of horses is 11
number of chicken is 1............Answer
Answer:
Step-by-step explanation:
5.