Answer:
Height of the silo = 18 feet.
Step-by-step explanation:
From the figure attached BC is the length of the silo and the height of the farmer is 5 ft.
Farmer is standing at 8 ft distance from the silo.
From triangle AEC,
tan(∠CAE) = CE/AE=5/8
m(∠CAE) = tan-1 (5/8)
= 32°
m∠BAE = 90° - 32° = 58°
From the triangle ABE,
tan58° = BE/AE
BE = 8tan58°
BE = 12.8 ft
Total height of the silo = BE + EC
= 12.8 + 5
= 17.8
≈ 18 ft
Therefore, the total height of the silo is 18 ft.
Hello!
I've altered the diagram and attached it below. I've added a circle; circles measure 360°. Segment CD is half the measure of the circle, thus it measures 180°. That means that if you add all the angle measures up, they have to equal 180°. Let's make an equation.
180 = (4x + 8) + 34 + (76 - x)
Now we can solve algebraically for x.
180 = 4x + 8 + 34 + 76 - x
180 = 3x + 118
62 = 3x
20.67 ≈ x
Answer:
x ≈ 20.67
Answer:
kilogram
Step-by-step explanation:
Answer:
(2,-6) Brainliest???
Step-by-step explanation:
The green line is x=y
I recomend to use desmos for questions like this ;)
The answer is negative. Read picture attached: make you a note for future reference.