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slamgirl [31]
3 years ago
7

Convert. (13/5) into a mixed number.

Mathematics
1 answer:
sladkih [1.3K]3 years ago
7 0

Answer:

2 3/5 :)

Step-by-step explanation:

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The correct answer is c x between 2 and 3
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Given that x = −2 and y = 5, what is the value of 3x+4y−2
pychu [463]

Answer:

12

Step-by-step explanation:

Note:

x = -2 ; y = 5

Plug in -2 for x and 5 for y.

3(-2) + 4(5) - 2

Remember to follow PEMDAS. First solve for multiplication, then combine:

3 * -2 = -6

4 * 5 = 20

-6 + 20 - 2

Combine like terms:

20 - 6 - 2 = 12

12 is your value.

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y-axis

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The score distribution shown in the table is for all students who took a yearly AP statistics exam. An AP statistics teacher had
Dmitrij [34]

Answer:

Step-by-step explanation:

The question is incomplete because the data is missing, i.e. the probability that you will score 5, 4, 3, 2, 1.

But it is resolved as follows:

P(x\geq  3) = P(\frac{x - m}{\frac{sd}{\sqrt{n} } } \geq \frac{3 - m}{\frac{sd}{\sqrt{n} }})\\\\

where m is the mean and sd is the standard deviation.

the m is calculated by the sum of the multiplication of the score by the probability of this  

that is to say,  

score   probability

  5           0.2

  4           0.3

  3            0.1

  2           0.3

  1             0.1

m = 5*0.2 + 4*0.3 + 3*0.1 + 2*0.3 + 1*0.1

m = 3.2  

However, the standard deviation will be calculated by

sd = \sqrt{\\}∑(x - m)^{2}*p

that is, knowing the mean already, we can calculate the standard deviation, following the example:

sd =\sqrt{[(5-3.2)^2] *0.2 + [(4-3.2)^2] *0.3 + [(3-3.2)^2] *0.1 + [(2-3.2)^2] *0.3 + [(1-3.2)^2] *0.1 }

sd = \sqrt{1.76}

sd = 1.327

And also n = 5, because it's 5 scores. We replace in the initial equation:

P(x\geq  3) = P(Z \geq \frac{3 - 3.2}{\frac{1.327}{\sqrt{5} }})\\\\

P(x\geq  3) = P(Z \geq -0.337)\\\\\\

Therefore for the example the number z is -0.337, which if in the normal distribution table corresponds to 0.3520, that is the probability that the average is at least 3, for the example is 35.20 %.

4 0
3 years ago
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