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lisov135 [29]
3 years ago
9

PLEASE HELP ME PLEASE!

Mathematics
1 answer:
maria [59]3 years ago
4 0
They can because of zero property. If we set them equal to zero we get their roots which is 3 and -2. This is the same on the x axis which is goes through. We can mark these points.
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Find the are of this compound shape below *
Alexandra [31]

Answer:

52 cm²

Step-by-step explanation:

First, we find the area of the bottom rectangle. We see it's 4 high and 10 wide, so 4x10 is 40. Then, we see that the small figure in the top right has a height of 4 and width of 3, so 4x3 = 12, add those and you get 52.

7 0
3 years ago
100 points !!!!!!! PLZ HELP
Olenka [21]

Answer:1. -6 ≤ x < -1 . . . . conjunction

2. x ≤ 6 . . or . . 10 ≤ x . . . . disjunction

3. 7 ≤ x < 12 . . . . conjunction

4. x < -9 . . or . . -3 ≤ x . . . . disjunction

5. 2 ≤ x ≤ 5 . . . . conjunction

6. x ≤ 54 . . or . . 66 ≤ x . . . . disjunction

7. 39 < x ≤ 43 . . . . conjunction

Step-by-step explanation:

I'm assuming its "Pattern". This is because its in a pattern of "Conjunction, Disjunction, Conjunction, Disjunction, etc." and theres 7 letters in the word Pattern.

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6 0
3 years ago
Read 2 more answers
Please help assaaaappp
inessss [21]
5k^2 = 25 ^ 3 = 15625
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Hope this helps
7 0
3 years ago
8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\&#10;\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\&#10;\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\&#10;\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\&#10;\mathsf{8x-32-9x+45=5}\\\\&#10;\mathsf{8x-9x=5+32-45}\\\\&#10;\mathsf{-x=-8}\\\\&#10;\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

7 0
3 years ago
Ujalakhan help! (x+2)(y-1) Simplify.
Gekata [30.6K]

Answer:

We can use the distributive property.

(x + 2)(y - 1)

= x(y) - x(1) + 2(y) - 2(1)

= xy - x + 2y - 2

4 0
3 years ago
Read 2 more answers
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