Question

A tennis ball is launched from a catapult from the ground with an initial velocity of 26fps. What is the maximum height of the ball? When will it attain this height? Use H=-16T2+26T

Answer 1

Answer:

10.5618feet, 0.8125sec

Step-by-step explanation:

Given the height reached by the catapult expressed by the equation H=-16T^2+26T

At the maximum height, the velocity of the object is zero, hence;

v = dh/dt = 0

-32t + 26 = 0

-32t = -26

t = 26/32

t = 0.8125secs

Hence it will attain the maximum height after 0.8125second

Substitute t = 0.8125s into the expression to get the maximum height

H=-16t^2+26t

H = -16(0.8125)^2 + 26(0.8125)

H = -16(0.6602) + 21.125

H = -10.5632+21.125

H = 10.5618

hence the maximum height reached by the ball is 10.5618feet