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tresset_1 [31]
3 years ago
9

Help please. due today, giving out brainliest to best answer

Mathematics
1 answer:
Korvikt [17]3 years ago
8 0

Answer:

-13, -17, -21.

Step-by-step explanation:

All you have to do is subtract it by 4 each term.

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8r-5q=3, solve for q
Stella [2.4K]
Subtract 8r over so it becomes
-5q=3-8r

Then divide both sides by -5
q= (3-8r)/-5
5 0
3 years ago
Read 2 more answers
Work out the sizes of each unknown exterior angle in this polygon
goldenfox [79]

Answer:

see explanation

Step-by-step explanation:

The sum of the exterior angles of a polygon = 360°

The exterior angle to interior angle is

exterior angle = 180° - 110° = 70°

Sum the exterior angles and equate to 360

x + 2x + 70 + 2x - 50 + x + 40 = 360 , that is

6x + 60 = 360 ( subtract 60 from both sides )

6x = 300 ( divide both sides by 6 )

x = 50

Then measure of exterior angles is

x = 50°

2x = 2 × 50 = 100°

x + 40 = 50 + 40 = 90°

2x - 50 = 2(50) - 50 = 100 - 50 = 50°

6 0
3 years ago
I need help NOW!!!!!! Thanks!
Mekhanik [1.2K]

Answer: Good thing you provided the image!

Working down the columns:

C base= 2

D base = 4

C height =3

D height = 2

C area = bh = 8

D area = bh = 8

Step-by-step explanation:

Try thinking about drawing a rectangle around the entire image of C and D, connecting each of the corners (sort of like what is being done for B) and then you can perceive the b and h.

The trick to D is to turn your head 90 degrees (or sideways) so you can see those 4 boxes as the base.

For C the base is the 2 boxes, and going up until you meet the other parallel side you can count 4 boxes.

I usually default to using the side which I can easily count boxes as the base and go from there.

4 0
3 years ago
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What is the polar form of Negative 9 StartRoot 3 EndRoot + 9 i?
kondor19780726 [428]

Answer:

Step-by-step explanation:

In the rectangular complex number -9√3 + 9i, which has a standard form a + bi, the a = -9√3 and the b = 9. We need this in polar form (r, θ) where

r=\sqrt{a^2+b^2} and filling in:

r=\sqrt{(-9\sqrt{3})^2+(9)^2 } (notice we do not put the i in there with the 9).

r=\sqrt{243+81} so

r = 18. Now let's move on to the angle, which is a little more difficult. The angle is found in the inverse tangent ratio:

tan^{-1}(\frac{b}{a}) so filling that in, we have:

tan^{-1}(\frac{9}{-9\sqrt{3} })=\frac{1}{-\sqrt{3} } Since tangent is the side opposite over the side adjacent, y is positive and x is negative in the second quadrant. This is a 30 degree angle in QII, which has a reference angle of 150 degrees. This angle in radians is \frac{5\pi}6}, so the polar form of that number is (18, \frac{5\pi}{6})

7 0
3 years ago
There are 340 students taking math 059 this semester. we found that 153 of them were male. about what percent of the students ta
svp [43]
45% of the math students taking Math 059 are males.
7 0
3 years ago
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