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2 years ago

Help please. due today, giving out brainliest to best answer

Mathematics

1 answer:

Korvikt [17]2 years ago

8 0

Answer:

-13, -17, -21.

Step-by-step explanation:

All you have to do is subtract it by 4 each term.

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Will the border line of the graph of y < - x2 + 4x + 5 be a solid line or a broken

Free_Kalibri [48]

Step-by-step explanation:

When the inequality uses < or >, it is a broken line.

For the point (0, 0) it means that x = 0 and y = 0.

Since (0) < (0)² + 4(0) + 5 is true, the point is part of the solution.

7 0

2 years ago

How to get an equivalent answer to 1/4

jasenka [17]

The answer to this equation is 1/2

6 0

3 years ago

HELP ASAP!! A recipe calls for 2.3 cup of milk. if you make 3 1/2 times the recipe, how much milk do you need?

LiRa [457]

The question is basically asking what 3.5 x 2.3 is. So the answer would be 8.05. If you read carefully it even tells you “times” I. The question. Hope this helps!!

3 0

2 years ago

to win a basketball game, one team scored 151 points. They made a total of 62 two-pointers and three pointers how many of the ba

wolverine [178]

That's a huge number of points.

First: Calculate the value of 62 two pointers

62 * 2 = 124

Second: find the number of points that were due to 3 pointers.

151 - 124 = 27

Third: Divide by 3 to find the number of 3 pointers.

27÷3 = 9

Answer: There were 9 three pointers.

3 0

3 years ago

The proportion of households in a region that do some or all of their banking on the Internet is 0.31. In a random sample of 100

Alenkasestr [34]

Answer:

Approximate probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is less than 0.0005% .

Step-by-step explanation:

We are given that let X be the number that do some or all of their banking on the Internet.

Also; Mean, $\mu$ = 310/1000 or 0.31 and Standard deviation, $\sigma$ = 14.63/1000 = 0.01463 .

We know that Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

Probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is given by P(X <= 130/1000);

P(X <=0.13) = P( $\frac{X-\mu}{\sigma}$ <= $\frac{0.13-0.31}{0.01463}$ ) = P(Z <= -12.303) = P(Z > 12.303)

Since this value is not represented in the z table as the value is very high and z table is limited to x = 4.4172.

So, after seeing the table we can say that this probability is approximately less than 0.0005% .

4 0

3 years ago