I’m not sure about number 9. But number 10 is answer C. This is because there are two sides to a coin, so you are equally likely to land on heads as you are tails. So you take 64 and divide it by 2, and get the answer 32.
First, factor out a 3.
3(x² - 9)
In any quadratic ax² + bx + c, we can split the bx term up into two new terms which we want to equal the product of a and c.
In this case, we have x² + 0x - 9. (the 0x is a placeholder)
We want two numbers that add to 0 and multiply to get -9.
Obviously, these numbers are 3 and -3.
Now we have 3(x² + 3x - 3x - 9).
Let's factor.
3(x(x+3)-3(x+3))
<u>3(x-3)(x+3)</u>
There are multiple shortcuts which you could make here, FYI:
Instead of splitting the middle, if your a value is 1, you can go straight to that step (x+number)(x+other number).
Whenever you have a difference of squares, like a²-b², that factors to (a+b)(a-b).
Answer: m = ½
.............................
-4m-24=-8
(add 24 to both sides)
-4m=16
(divide by -4 on both sides)
m=-4
Answer:
Nice to hear that, congrats with practice 7.3
