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3 years ago

(-2,-6) and (-6,10) write the equation of the line with the given points in slope intercept form

Mathematics

1 answer:

Stels [109]3 years ago

5 0

The coordinate points (-2,-6) and (-6,10) written in slope-intercept form is...

y = -4x + -14

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The functions r and s are defined as follows.

Arlecino [84]

Answer:

r o s(3)=?

s(x)= x²-1

x=3

s(3)= 3²-1

s(3)= 9-1

s(3)=8

r(8)

r(x)= -2x-1

x=8

r(8)= -16-1

r(8)= -17

r(s(3))= -17

6 0

2 years ago

Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find

Papessa [141]

Answer:

1) $\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) $\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) $\text{P(at least two girls)}=\frac{1}{2}$

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To Find : The probability of each event.

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

1) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, BGG, GBB, GBG, GGB=6

$\text{P(at least one boy and one girl)}=\frac{6}{8}$

$\text{P(at least one boy and one girl)}=\frac{3}{4}$

2) P(at least one boy and one girl)

Favorable outcome = BBG, BGB, GBB=3

$\text{P(at least one boy and one girl)}=\frac{3}{8}$

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

$\text{P(at least two girls)}=\frac{4}{8}$

$\text{P(at least two girls)}=\frac{1}{2}$

4 0

3 years ago

Read 2 more answers

PLEASEEEEEE HELPPPPPPPPPP MEEEEEEEEEEEEEEEE

polet [3.4K]

Answer:

120.2 or in other words, the answer is the last option, D

3 0

3 years ago

If sin ? = 12 over 37, use the pythagorean identity to find cos ?. cos ? = ± 35 over 37 cos ? = ± 23 over 37 cos ? = ± 35 over 1

kotegsom [21]

If sin x = 12/37, we have to find cos x.
The identity:
sin² x + cos² x = 1
( 12/37)² + cos² x = 1
144 / 1369 + cos² x = 1
cos² x = 1 - 144/1369
cos² x = 1369/1369 - 144/1369
cos² x = 1225 / 1369
cos x = +/- √ 1225/1369 = +/- 35/37
Answer:
A ) cos ? = +/- 35 over 37

7 0

3 years ago

Read 2 more answers

4x+3y=10 and -6x-5y=-16

dimaraw [331]

Answer:

Okay, Tell em what ur trying to ask please :/- confused

Step-by-step explanation:

6 0

3 years ago