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3 years ago

(-2,-6) and (-6,10) write the equation of the line with the given points in slope intercept form

Mathematics

1 answer:

Stels [109]3 years ago

5 0

The coordinate points (-2,-6) and (-6,10) written in slope-intercept form is...

y = -4x + -14

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Historical data for a local manufacturing company show that the average number of defects per product produced is 2. In addition

charle [14.2K]

Answer:

The probability that there will be a total of 7 defects on four units is 0.14.

Step-by-step explanation:

A Poisson distribution describes the probability distribution of number of success in a specified time interval.

The probability distribution function for a Poisson distribution is:

$P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}, x=0,1,2,3,...$

Let <em>X</em> = number of defects in a unit produced.

It is provided that there are, on average, 2 defects per unit produced.

Then in 4 units the number of defects is, $(2\times4)=8$ .

Compute the probability of exactly 7 defects in 4 units as follows:

$P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}\\P(X=7)=\frac{e^{-8}8^{7}}{7!}\\=\frac{0.0003355\times2097152}{5040}\\ =0.1396\\\approx0.14$

Thus, the probability of exactly 7 defects in 4 units is 0.14.

8 0

3 years ago

Write the following statement as an equation

puteri [66]

Answer:

The answer is: b5y + 9 = 16

3 0

3 years ago

Read 2 more answers

6y+2+9x how many terms are there in the algebraic expression

TiliK225 [7]

Answer: 3

Step-by-step explanation:

6y (1)

2 (2)

9x (3)

7 0

3 years ago

Are these triangles similar

Gre4nikov [31]

Answer:

Step-by-step explanation:

It's not similar because when aligning the values they don't match. 3 × 5 = 15 so that bottom line matches but when you do the same thing to the other line: 5 × 3 does not equal 9. There is no similarity between the two triangles.

3 0

3 years ago

Factor the following trinomial. (Hint: Solve the equations first.)<br><br> x²-2x-2

Alex_Xolod [135]

Answer:

$(x-(1+\sqrt{3}))(x-(1-\sqrt{3}))$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} -2x-2=0$

$a=1\\b=-2\\c=-2$

substitute in the formula

$x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-2)}} {2(1)}$

$x=\frac{2(+/-)\sqrt{12}} {2}$

$x=\frac{2(+/-)2\sqrt{3}} {2}$

$x_1=\frac{2(+)2\sqrt{3}} {2}=1+\sqrt{3}$

$x_2=\frac{2(-)2\sqrt{3}} {2}=1-\sqrt{3}$

therefore

$x^{2} -2x-2=(x-(1+\sqrt{3}))(x-(1-\sqrt{3}))$

5 0

3 years ago