Here's how you solve this. So, x+y=2, right? Let's isolate x. x+y-y=2-y. x=2-y. NOW, if x=2-y, in 3x+2y=5, we can REPLACE x with 2-y and use it to solve for y! 3x+2y=5. 3(2-y)+2y=5. (3*2)+(3*-y)+2y=5. 6+(-3y)+2y=5. 6+(-y)=5. 6+(-y)-6=5-6. -y=-1. -y/-1=-1/-1. y=1.
So, if y=1, we can substitute that back into either equation--but let's go with the easier one, x+y=2. x+1=2. x+1-1=2-1. x=1. 1+1=2, so that works; let's check the other equation. 3(1)+2(1)=5. 3+2=5. 5=5. That's correct!
Answer: x=1, y=1
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Answer:
<em>The answer is 0</em>
<em>So I think no solutions</em>
Step-by-step explanation:
You gotta get each equation into slope-intercept form, nd when u do that 9x - 3y = 6 turns into y = 3x - 2, nd 5y = 15x + 10 turns into y = 3x + 2. Add the equations together, nd get 0.
Answer:
students in the drama club: 57
students in the yearbook club: 44
Step-by-step explanation:
101 - 13 = 88
88 / 2 = 44
101 - 44 = 57
44 in the drama club and 57 in the yearbook club
