I believe you are asking in how many ways they can sit. If so:
The 1st can sit anywhere: he has only 1 way to sit
The 2nd can sit in 11 ways, since one seat is already occupied
The 3rd can sit in 10 ways, since 2 seat are already occupied
The 4th can sit in 9 ways, since 3 seat are already occupied
The 5th can sit in 8 ways, since 4 seat are already occupied
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The 12th can sit in 1 way, since11 seat are already occupied
General formula for a circular table:
Number of ways they n persons can be seated: (n-1)!
and the 12 can be seated in (12-1)! = 11! = 39,916,800 ways.
This is called circular permutation
Answer:
1 /4, 4/9,9/16,16/25 25/36,49/64 10th term 130/111
Step-by-step explanation:
Nominator increasing: +3 +5 +7 +9 +11 +13.......
Denominator 2^,3^,4^,5^...........
1+3=4
4+5=9
9+7=16
16+9=25
25+11 =36
36+13=49.....
2^=4 3^=9 4^=16.......
F(-3) = (-3)^4 + 3(-3)^3 - (-3)^2 +6
f(-3)= 81 -81 -9 +6
f(-3)= -3
Answer:
3
Step-by-step explanation:
share 30 in the ratio 1:9
1+9=10
30÷10 =3
3 in each part
