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kiruha [24]
3 years ago
8

Hii please help i’ll give brainliest

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0

Answer:

A :) Sorry if it's wrong, I'm learning this too

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Show that sec^2x+csc^2x/sec^2xcsc^2x
professor190 [17]

Answer:

\frac{1}{csc^{2}(x)}+\frac{1}{sec^{2}(x)}

Step-by-step explanation:

The image below shows step-by-step on how to solve it.

<em>Hope this helps! </em>:)

4 0
3 years ago
(a) Michael bought 19 pounds of sugar for $8. How many dollars did he pay per pound
Dmitrij [34]

Answer:

A = 2.37500

B = 8.5

Step-by-step explanation:

Explanation A - 19 divided by 8 is 2.37500

Explanation B - 34 divided by 4 is 8.5

6 0
3 years ago
How to graph 9x+5y=-45
lilavasa [31]
9x +5y= -45 put in standard form y= mx+b coefficient of x is the slope, b is the y intercpept 5y= -9x -45 y= -9/5 x -45 graphing will start at -45 on the y axis from that point go down 9 to the right 5 for the slope continue and graph minimum 2 points to draw the line hope this helps
8 0
3 years ago
Find the limit, if it exists, or type dne if it does not exist.
Phantasy [73]
\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}

Suppose we choose a path along the x-axis, so that y=0:

\displaystyle\lim_{x\to0}\frac{x^2}{x^2}=\lim_{x\to0}1=1

On the other hand, let's consider an arbitrary line through the origin, y=kx:

\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}

The value of the limit then depends on k, which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.
8 0
4 years ago
Two way to solve g+94=75
Tamiku [17]

Answer:

g = -19

Step-by-step explanation: You have to isolate g

g + 94 = 75

   - 94   - 94

g = -19


Sorry if I'm incorrect...

5 0
3 years ago
Read 2 more answers
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