HELP! Factor and Write an equivalent expression for 36a

What are the zeros of the polynomial function? <br><br> F(x)= x^2 +12x

Pavel [41]

Answer:

x = 0 and x = -12 are the two zeroes

Step-by-step explanation:

"Zeroes" of a function are also called the solutions, roots or x intercepts.

The zeroes are the numbers that give the function a values of 0, so find what value for 'x' yields F(x) = 0 as a result.

With quadratic equations (equations with x² as the largest exponent), you factor the equation.

Step 1: Set the equation equal to zero

x² + 12x = 0

Depending on the equation, there are several methods you can use to factor, for this one we can factor out an 'x' since both terms have an 'x' in them. We get...

x(x + 12) = 0

So now, using the "zero product property" which means that if two things are multiplied together, and the result is zero, then either the first term is zero, the second term is zero, or they are both zero. So we set each term equal to zero and solve.

So

either x = 0 or x + 12 = 0

Solve each for x to get your two anwers.

x= 0 is already solved, so 0 is our first zero

Now solve

x + 12 = 0

x = -12 (subtract 12 from both sides to isolate x)

8 0

3 years ago

What is the value of 1 x ÷ 5, when x = 80? enter your answer in the box.

slava [35]

Insert 80 into the equation
1(80) / 5
80/5 = 16

7 0

3 years ago

Read 2 more answers

6n+3=2 use a table ....

kvasek [131]

You - 3 from 2 then do 6n=-1

6 0

3 years ago

Write seven hundred two and six hundred fifty-six thousandths in standard form and in expanded form.

Naddik [55]

Standard Form: 702.656
Expanded Form: 700+2+0.6+0.05+0.006

7 0

3 years ago

g A certain financial services company uses surveys of adults age 18 and older to determine if personal financial fitness is cha

leva [86]

Answer:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

$z=\frac{0.410-0.35}{\sqrt{0.385(1-0.385)(\frac{1}{1000}+\frac{1}{700})}}=2.502$

$p_v =2*P(Z>2.502)= 0.0123$

Comparing the p value with the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to to reject the null hypothesis, and we can say that the proportion analyzed is significantly different between the two groups at 5% of significance.

Step-by-step explanation:

Data given and notation

$X_{1}=410$ represent the number of people indicating that their financial security was more than fair for the recent year

$X_{2}=245$ represent the number of people indicating that their financial security was more than fair for the year before

$n_{1}=1000$ sample 1 selected

$n_{2}=700$ sample 2 selected

$p_{1}=\frac{410}{1000}=0.410$ represent the proportion estimated of indicating that their financial security was more than fair this year

$p_{2}=\frac{245}{700}=0.35$ represent the proportion estimated of indicating that their financial security was more than fair the year before

$\hat p$ represent the pooled estimate of p

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{410+245}{1000+700}=0.385$

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.410-0.35}{\sqrt{0.385(1-0.385)(\frac{1}{1000}+\frac{1}{700})}}=2.502$

Statistical decision

Since is a two sided test the p value would be:

$p_v =2*P(Z>2.502)= 0.0123$

Comparing the p value with the significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to to reject the null hypothesis, and we can say that the proportion analyzed is significantly different between the two groups at 5% of significance.

7 0

3 years ago

HELP! Factor and Write an equivalent expression for 36a - 16. THANKS