4x + 30 = 5x + 20
30 - 20 = 5x - 4x
10 = x <==
Answer:
HCF Of two nos. is 17
Let another no. be x
we know that HCF ×LCM = Product of two numbers
17×140=20×(x)
20x=2380
x =2380/20
x=119
The other no. is 119
11(6)-14=56
The answer should be 9x+2 which would be 56–> 9(6)+2=56
Answer:
We are effectively looking for a and b such that 5, a, b, 135 is a geometric sequence.
This sequence has common ratio <span><span>3<span>√<span>1355</span></span></span>=3</span>, hence <span>a=15</span> and <span>b=45</span>
Explanation:
In a geometric sequence, each intermediate term is the geometric mean of the term before it and the term after it.
So we want to find a and b such that 5, a, b, 135 is a geometric sequence.
If the common ratio is r then:
<span><span>a=5r</span><span>b=ar=5<span>r2</span></span><span>135=br=5<span>r3</span></span></span>
Hence <span><span>r3</span>=<span>1355</span>=27</span>, so <span>r=<span>3<span>√27</span></span>=3</span>
Then <span>a=5r=15</span> and <span>b=ar=15⋅3=45</span>
