The confidence level and sample data to find a confidence interval for estimating the population mu. round your answer to the same number of decimal places as the sample mean 88.2 < μ < 93.0.
<h3>What are the confidence level?</h3>
The confidence stage refers to the proportion of probability, or certainty, that the self-belief c language could include the real populace parameter whilst you draw a random pattern many times.
- We have this given info:
- n = 92 = pattern length xbar = 90.6 = pattern imply
- sigma =8.! = populace popular deviation
- C=99% self-assurance level
- Because n > 30 and due to the fact we recognize sigma, this permits us to apply the Z distribution (aka popular ordinary distribution).
- At 99% self-assurance, the z essential price is more or less z = 2.576 use a reference sheet, table, or calculator to decide this.
- The decrease sure of the self assurance c programming language (L) is more or less L = xbar - z*sigma/sqrt(n) L = 90.6-2.576*8.9/sqrt(92) perp= 88.209757568781 perp= 88.2
- The top sure (U) of this self assurance c programming language is more or less U = xbar + z*sigma/sqrt(n) L = 88.209757568781 L = 88.2.
- The top sure (U) of this self assurance c programming language is more or less U=xbar+z^ * sigma/sqrt(n) U = 90.6 + 2.576*8.9/sqrt(92) U = 92.990242431219
- U = 93.0.
- Therefore, the self assurance c programming language withinside the format (L, U) is about (88.2, 93.zero).
Read more about the population :
brainly.com/question/25896797
#SPJ1
I don’t think that’s possible cause it’s mostly always anonymous
Answer: You could start a reddit discussion.
Explanation:
Reddit draws in a lot of people in so you could get feedback easily
what do you mean all I see is Gianna is going to throw a ball from the top floor
