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3 years ago

Need help please and thank you

Mathematics

1 answer:

Juli2301 [7.4K]3 years ago

3 0

It would be C because it’s asking you to multiple 3/4 by 3/4 sense there is a 2 exponent. And in order to multiply fractions you multiply across the top and bottom and then simplify. Sense c is already simplified that would be your answer. 3 x 3
4x4 9/16 or c

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Is the following number rational or irrational?<br> 9.0<br> A: rational<br> B: Irrational

Lelu [443]

Answer:

Rational

Explanation:

9 is a Rational Number

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3 years ago

Simplify (9^2/3*9^4/2)/9^1/2

JulsSmile [24]

Answer:

$\frac{9^{5}}{3}$

Step-by-step explanation:

$\frac{9^{2}}{3} * \frac{9^{4}}{2} = \frac{9^{6}}{6}\\\\\frac{\frac{9^{6}}{6}}{\frac{9^{1}}{2}} \\\\\frac{2*9^{6}}{6*9^{1}}\\\\\frac{9^{5}}{3}$

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3 years ago

A house has increased in value by 37% since it was purchased. If the original value was $720, 000, what is the value after the i

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2 years ago

How would you solve that problem

antiseptic1488 [7]

Since you that that line is 180 degrees you can simply do 180-149 and find that the answer is 31 degrees. So you would do 13x+5=31, 31-5=26, 26/13, and then x=2 :)

7 0

4 years ago

Can you please help me out

Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

$\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}$

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

$\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}$ $\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}$

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

$\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}$

Hence, the best option is G.

5 0

1 year ago