Answer:
A) B is greater
B) when C = 21, A = 5 and B = 15
C) A must be 0, 5, or 12 for C to be greater than B
Step-by-step explanation:
A) when a = -3, c = -20 and b = 4(-3)-5 so B = -17
B) when c = 21, a = 5 and b = 4(5)-5 so B = 15
C) C is greater than B when a = 0, 5, and 12
when a = 0, b = 4(0)-5 or -5
when a = 5, b = 4(5)-5 or 15
when a = 12, b = 4(12)-5 or 43
-5/11 is what I got with a fraction calculator.
Step-by-step explanation:
the introduction of a fraction tells us that we are dealing with multiplications, and therefore a geometric sequence (where every new term is created by multiplying the previous term by a constant factor, the ratio r).
I think your teacher made a mistake, or you made one when typing the question in here.
there is no factor r that creates
15×r = 9
and
9×r = 5/27
it would mean that
15 × r² = 5/27
r² = 5/27 / 15 = 5/27 × 1/15 = 5/405 = 1/81
r = 1/9
but 15 × 1/9 = 5 × 1/3 = 5/3 is NOT 9
and 9 × 1/9 = 9/9 = 1 is NOT 5/27
so, this can't be right.
on the other hand
15 × r = 9
r = 9/15 = 3/5
and then
9 × 3/5 = 27/5
so, either the sequence should have been
15, 5/3, 5/27
or (and I suspect this to be true)
15, 9, 27/5
under that assumption we have
s1 = 15
r = 3/5
sn = sn-1 × r = s1 × r^(n-1) = 15 × (3/5)^(n-1)
s10 = 15 × (3/5)⁹ = 15 × 19683/1953125 =
= 3 × 19683/390625 = 59049/390625 =
= 0.15116544 ≈ 0.151
Answer:
C. quadratic function; quadratic term: −6x^2; linear term: −17x; constant term: −12
Step-by-step explanation:
Answer:
quadratic function; quadratic term: −6x² ; linear term: −17x; constant term: −12
Step-by-step explanation:
The given function is
We need to expand the RHS to get:
We can see that the degree of this polynomial function is 2 and hence it is a quadratic function.
The quadratic term is -6x²
The linear term is -17x
The constant term is -12
The total cost curve shows the cost of total shipment from the different
cities.
- a. Please find attached the graph of the total cost to quantity of shipment created with MS Excel.
- b. The city that provides the lowest overall cost is; <u>Salt Lake City</u>.
Reasons:
The given parameters are;
The number of shipment per = From 550,000 to 600,000 per year
The given table is presented as follows;
![\begin{tabular}{|l|c|c|c|}Location&Annual Fixed Costs&Variable Cost \\Denver&\$5,000,000&\$4.65 \\Santa Fe&\$4,200,000&\$6.25\\Salt Lake City&\$3,500,000&\$7.25\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%7B%7Cl%7Cc%7Cc%7Cc%7C%7DLocation%26Annual%20Fixed%20Costs%26Variable%20Cost%20%5C%5CDenver%26%5C%245%2C000%2C000%26%5C%244.65%20%5C%5CSanta%20Fe%26%5C%244%2C200%2C000%26%5C%246.25%5C%5CSalt%20Lake%20City%26%5C%243%2C500%2C000%26%5C%247.25%5Cend%7Barray%7D%5Cright%5D)
a. Required:
The plot total cost curve for the locations on a single graph.
Solution:
- Please find attached the graph of the total cost curves created with MS Excel
b. Required:
The city that provides the lowest overall cost.
Solution:
The two cities with the lowest overall costs are Denver and Salt Lake City.
- From the total cost curve, the area under the curves are;
Area under the curve for Denver;
(7557500 + 7790000) ÷ 2 × 50,000 = 383687500000
Area under the curve for Salt Lake City
(7487500 + 7850000) ÷ 2 × 50,000 = 383437500000
Therefore;
- <u>Salt Lake City provides the lowest overall costs</u>.
Learn more about total cost curves here:
brainly.com/question/4888738