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musickatia [10]
3 years ago
5

Pleaseee :(((((((((((((((

Mathematics
1 answer:
Pepsi [2]3 years ago
7 0

<em>Vertex: </em>(-3,5)<em />

<em>The vertex is the top point where it curves!</em>

<em>Which is located at: </em>(-3,5)<em />

<em />

<em>Y-intercept: </em>(0,3.2)<em />

<em>The Y-intercept is when a point doesn't move or left or right and just goes up or down!</em>

<em />

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Point S is the point of concurrency of the angle bisectors of ΔWXY. Triangle W X Y is shown. Point S is the point of concurrency
alexandr1967 [171]

Answer: SU=5

Step-by-step explanation:

4 0
3 years ago
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It is known that there only is 1% chance of getting a disease. a test is being devised to detect the disease. the probability th
Cerrena [4.2K]
Suppose D is the event that a given patient has the disease, and P is the event of a positive test result.

We're given that

\mathbb P(D)=0.01
\mathbb P(P\mid D)=0.98
\mathbb P(P^C\mid D^C)=0.95

where A^C denotes the complement of an event A.

a. We want to find \mathbb P(P^C). By the law of total probability, we have

\mathbb P(P^C)=\mathbb P(P^C\cap D)+\mathbb P(P^C\cap D^C)

That is, in order for P^C to occur, it must be the case that either D also occurs, or D^C does. Then from the definition of conditional probability we expand this as

\mathbb P(P^C)=\mathbb P(D)\mathbb P(P^C\mid D)+\mathbb P(D^C)\mathbb P(P^C\mid D^C)

so we get

\mathbb P(P^C)=0.01\cdot0.02+0.99\cdot0.95=0.9407

b. We want to find \mathbb P(D\mid P). Now, we can use Bayes' rule, but if you're like me and you find the formula a bit harder to remember, we can easily derive it.

By the definition of conditional probability,

\mathbb P(D\mid P)=\dfrac{\mathbb P(D\cap P)}{\mathbb P(P)}

We have the probabilities of P/P^C occurring given that D/D^C occurs, but not vice versa. However, we can expand the probability in the numerator to get a probability in terms of P being conditioned on D:

\mathbb P(D\cap P)=\mathbb P(D)\mathbb P(P\mid D)

Meanwhile, the law of total probability lets us rewrite the denominator as

\mathbb P(P)=\mathbb P(P\cap D)+\mathbb P(P\cap D^C)

or in terms of conditional probabilities,

\mathbb P(P)=\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)

so that

\mathbb P(D\mid P)=\dfrac{\mathbb P(D)\mathbb P(P\mid D)}{\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)}

which is exactly what Bayes' rule states. So we get

\mathbb P(D\mid P)=\dfrac{0.01\cdot0.98}{0.01\cdot0.98+0.99\cdot0.05}\approx0.1653
6 0
3 years ago
Researchers conducted an experiment to test the effects of alcohol. Errors were recorded in a test of visual and motor skills fo
Jobisdone [24]

Answer:

H0: σ1=σ2

Ha : σ1 >σ2

B. Upper H 0H0​:

sigma Subscript 1 Superscript 2σ21equals=sigma Subscript 2 Superscript 2σ22

Upper H 1H1​:

sigma Subscript 1 Superscript 2σ21greater than>sigma Subscript 2 Superscript 2σ22

Step-by-step explanation:

The claim is  that the treatment group has errors that <em><u>vary significantly</u></em> more than the errors of the placebo group.

The claim is the alternative hypothesis and the opposite of claim is the null hypothesis.

Vary significantly means that it is greater than so we choose the alternate hypothesis of greater than and the null hypothesis will be equal to errors of the placebo group.

So the correct choice is B.

B. Upper H 0H0​:

sigma Subscript 1 Superscript 2σ21equals=sigma Subscript 2 Superscript 2σ22

Upper H 1H1​:

sigma Subscript 1 Superscript 2σ21greater than>sigma Subscript 2 Superscript 2σ22

Choice A,C and D all are incorrect.

This can be written as

H0: σ1=σ2

Ha : σ1 >σ2

5 0
3 years ago
Please help me out 5x + 2 +3x + 5​
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Answer:

8x + 7

Step-by-step explanation:

combine the like terms

8 0
3 years ago
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Which expression results from using the Distributive Property? 2(5 + 3r)
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Answer:

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Explanation:

2(5 + 3r)

= (2)(5 + 3r)

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= 10 + 6r

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5 0
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