Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or 
ft
= 
ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
= 
ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k()
k = 18
Work done (W) to stretch the spring by ft will be
W = 
= 
= ![18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0](https://tex.z-dn.net/?f=18%5B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%5D%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D_0)
= 9()²
= 7.56 lb-ft
Answer:
Cluster sample
Step-by-step explanation:
i did it before
Answer:
a) 0.0137060668
please mark me brainliest and follow me my friend.
I not know b part.
The answer is 5 5/6 simplified to the max.
rewrite the equation with separated parts
-3 1/2 - 2 1/3
-3 - 2 = -5
-1/2 - 1/3? u need to find the LEAST common denominator
-3/6 - 2/6 = -5/6
how did I get 6?
Rewriting input as fractions if necessary:
1/2, 1/3
For the denominators (2, 3) the least common multiple (LCM) is 6.
Therefore, the least common denominator (LCD) is 6.
Now lastly combine them total and its -5 - 5/6 = -5 5/6.
Answer:
Each teacher will have 21 students
Step-by-step explanation:
273 divded by 21 = 21
