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Thepotemich [5.8K]
3 years ago
7

Step by step 7 ,9, and 11 please. EVEN IF U CANT DO ALL, u can help with 1 or 2. Ill mark brainly.

Mathematics
1 answer:
gregori [183]3 years ago
5 0

Answer:

7) 4 \ log_3(x) - 4 \ log_3(y)

9) 5log_4(7) - 5log_4(12)

11) 5log_5 \ (x) - log_5 \ (y)

Step-by-step explanation:

log_3 (\frac{x}{y})^{4}

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Use Logarithm of a Quotient which states

log_b \frac{M}{N}  = log_b M-log_bN

And also use Logarithm of a Power which states

log_b\ M^{n} = n\log_bM

----------------------------------------------------------------------------------------------------

So using these two properties,

7. 4 \ log_3(x) - 4 \ log_3(y)

----------------------------------------------------------------------------------------------------

----------------------------------------------------------------------------------------------------

For #9, use the same logarithm propertied

log_4(\frac{7}{12})^5 = 5log_4(7) - 5log_4(12)

----------------------------------------------------------------------------------------------------

----------------------------------------------------------------------------------------------------

#11 is also the same concept

log_5\ \frac{x^5}{y} = 5log_5 \ (x) - log_5 \ (y)

It is not  - 5 log5(y) since only x is to the power of 5 not y

----------------------------------------------------------------------------------------------------

Hope this is what you were looking for and helps you! Have a nice day/night :)

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drek231 [11]

An expression for the total cost of the daycare for Lucy's dog this week is T = 3F + 2H and the total cost is equal to $114.

<h3>How to write an expression for the total cost?</h3>

In this exercise, you're required to write an expression for the total cost of the daycare for Lucy's dog this week. Thus, we would assign a variable to the cost for full-day and half-day day care as follows:

  • Let the cost for full-day be F.
  • Let the cost for half-day be H.
  • Let total cost be T.

Thus, the total cost of the daycare is given by:

T = 3F + 2H

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3 years ago
Plssss help quick i need it for sum important
Vanyuwa [196]

(a) The product of (2x-4)\ and\ (3x^2-x+4)  is calculated to be =6x^3-14x^2+12x-16

(b)The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

<u>Step-by-step explanation:</u>

<u>(a)</u>

(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16

b)

(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8

The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

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