Question

Three raised to the square of a number, x, is equal to nine raised to the power two times the same number x decreased by one.

Answer 1

Answer:

Step-by-step explanation:

$3^x^2=9^{2x-1}\\3^x^2=(3^2)^{2x-1}\\x^2=4x-2\\x^2-4x+2=0\\X^2-4X+4=-2+4\\(X-2)^2=2\\|x-2|=\pm \sqrt{2} \\x=2+\sqrt{2},2-\sqrt{2}$