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Answer:
Part A
The bearing of the point 'R' from 'S' is 225°
Part B
The bearing from R to Q is approximately 293.2°
Step-by-step explanation:
The location of the point 'Q' = 35 km due East of P
The location of the point 'S' = 15 km due West of P
The location of the 'R' = 15 km due south of 'P'
Part A
To work out the distance from 'R' to 'S', we note that the points 'R', 'S', and 'P' form a right triangle, therefore, given that the legs RP and SP are at right angles (point 'S' is due west and point 'R' is due south), we have that the side RS is the hypotenuse side and ∠RPS = 90° and given that =
, the right triangle ΔRPS is an isosceles right triangle
∴ ∠PRS = ∠PSR = 45°
The bearing of the point 'R' from 'S' measured from the north of 'R' = 180° + 45° = 225°
Part B
∠PRQ = arctan(35/15) ≈ 66.8°
Therefore the bearing from R to Q = 270 + 90 - 66.8 ≈ 293.2°
Part A: The solution is
Part B: The point is not in the solution set.
Explanation:
Part A: The given inequalities are and
The solution can be determined by solving the two inequalities by substitution method.
Changing inequalities to equality, we have,
and
Let us substitute in the equation
, we get,
Substituting in
, we get,
Thus, the solution set is
Part B: Now, we shall determine whether the point is in the solution set.
Let us substitute the point in the inequalities
and
, we get,
Also, substituting in
, we get,
Since, the point does not satisfy one of the inequality
, the solution set does not contain the point
Thus, the point is not in the solution set.