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dimulka [17.4K]
3 years ago
10

In the diagram, the measure of angle 6 is 98 degrees. what is the measure of angle 7?

Mathematics
1 answer:
just olya [345]3 years ago
8 0

Answer:

82

Step-by-step explanation:

180-98. it's easy.

please mark me brainliest so I can get to Ace rank

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Add the who numbers: 4 + 2 = 6

You are correct, it's C. 6
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If it takes Mr. Williams 1/5 hour to grade each of his students’ tests, how many tests can he grade in 4 hours?
MaRussiya [10]

Answer:

1234567891011121314151617181920

7 0
3 years ago
Read 2 more answers
(7)8 - 6 divided by 2 + (A)3 = 107. What is A?
Hunter-Best [27]

\huge\fbox{Answer ☘}

7(8) - 6 \div 2 + (a)3 = 107 \\ 56 - 3 + 3a = 107 \\ 53 + 3a = 107 \\ 3a = 107 - 53 \\ 3a = 54 \\ a =  \cancel\frac{54}{3}  = 18

hope helpful~

7 0
3 years ago
En una tienda de ropa vas a comprarte una pantalones que están de 150 a 90 euros y una camiseta de 40 a 24 ¿ tienen el mismo por
uranmaximum [27]

Respuesta:

Sí, tienen el mismo descuento del 40%

Explicación paso a paso:

Dado :

PANTALÓN :

Precio inicial = 150

Precio con descuento = 90

Porcentaje de descuento en el precio:

(150 - 90) / 150 * 100%

60/150 * 100%

0,4 * 100

= 40%

CAMISA:

Precio inicial = 40

Precio con descuento = 24

Porcentaje de descuento en el precio:

(40-24) / 150 * 100%

16/40 * 100%

0,4 * 100

= 40%

Sí, tienen el mismo descuento del 40%

8 0
3 years ago
After your yearly checkup, the doctor has some bad news and some good news. The bad news is that you tested positive for a serio
Maru [420]

Answer:

0.009804

Step-by-step explanation:

We are given;

probability of testing positive given that you have the disease is 0.99

Also, probability of not testing positive and not having the disease is 0.99

We are also told that it is a rare disease and so strikes only 1 in 1000 people = 0.0001

Let's denote positive test by T+, negative test by T¯, having the disease by D+, not having the disease by D¯.

So, we can now denote all the values in probability we have written earlier.

Thus:

P(T+ | D+) = 0.99

P(T¯ | D¯) = 0.99

P(D+) = 0.0001

Thus, P(D¯) = 1 - P(D+) = 1 - 0.0001 = 0.9999

Now, let's find probability of testing positive;

P(T+) = (P(T+ | D+) × P(D+)) + (P(T+ | D¯) × P(D¯))

Now, (P(T+ | D¯) is not given but by inspection, we can infer from the values given that it is 0.01

Thus;

P(T+) = (0.99 × 0.0001) + (0.01 × 0.9999)

P(T+) = 0.010098

Chances that one has the disease would be gotten from Baye's theorem;

P(D+ | T+) = (P(T+ | D+) × P(D+))/P(T+) = (0.99 × 0.0001)/0.010098 = 0.009804

7 0
3 years ago
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