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2 years ago

10

what is this area? marking brainliest if more than one answers and giving thanks to correct! giving thanks to who can help in ge

neral, thank you

2 answers:

statuscvo [17]2 years ago

6 0

Answer:

57

Step-by-step explanation:

i hope its that

7x3+9x4

=57

sesenic [268]2 years ago

4 0

Answer:

thirty two I think hope it's right

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Austin buys $10 worth of food for his dog each week. There are 52 weeks in a year.

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Step-by-step explanation:

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2 years ago

In this graph, the y-intercept of the line is ___.<br> The equation of the line is y=__ x __.

KonstantinChe [14]

Answer:

In this graph, the y-intercept of the line is -2, if the coordinates are needed, its (0,-2). The equation of the line is y= x-2 ( slope intercept form ).

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2 years ago

What is the value of the expression (2)^6?<br>pls help

Ronch [10]

Answer:

64

Step-by-step explanation:

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Basically you multiply the bottom number (in this case 2) by itself as many times as the the number in the top right (in this case six)

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8 0

2 years ago

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Can the sides of a triangle have lengths 2, 7, and 8?

Natalka [10]

Answer:

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Step-by-step explanation:

As long as any two numbers added are greater than the number not chosen they can make a triangle

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3 0

2 years ago

Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

<u>Algebra I</u>

Factoring

<u>Calculus</u>

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

<u>Step 1: Define</u>

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

<u>Step 2: Differentiate Pt. 1</u>

<em>Find 1st Derivative</em>

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate <em>y'</em> terms: $-xy' - 2y' = y$
[Algebra] Factor <em>y'</em>: $y'(-x - 2) = y$
[Algebra] Isolate <em>y'</em>: $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

<u>Step 3: Find </u><em><u>y</u></em>

Define equation: $-xy - 2y = -4$
Factor <em>y</em>: $y(-x - 2) = -4$
Isolate <em>y</em>: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

<u>Step 4: Rewrite 1st Derivative</u>

[Algebra] Substitute in <em>y</em>: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

<u>Step 5: Differentiate Pt. 2</u>

<em>Find 2nd Derivative</em>

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$

<u>Step 6: Find Slope at Given Point</u>

[Algebra] Substitute in <em>x</em>: $y''(-1) = \frac{8}{(-1+2)^3}$
[Algebra] Evaluate: $y''(-1) =8$

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2 years ago

Read 2 more answers