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Oliga [24]
3 years ago
13

Plz help plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz 50 points

Mathematics
1 answer:
butalik [34]3 years ago
7 0

Answer:

d1 = 192

d2 = 192

Step-by-step explanation:

step 1

From the imformation given, the distance is the same

so from the table

d1 = 64t

d2 = 48(7-t)

the distance is the same, it means

d1 = d2

therefore we can get the time(t) from here

64t = 48(7-t)

64t = 336 - 48t

collect like terms

64t+48t = 336

112t = 336

t = 336/112

t = 3

substitute t into d1 to get the distance

d1 = 64t

d1 = 64 × 3

d1 = 192

Note, d1 = d2

d2 = 192 too

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Write a real world problem that can be solved using the equation 38 divided by 5 = 7 r 3
notka56 [123]
You are having a birthday party and invited 38 people.  Each table you rented only sits 5 people. 
 
How many tables would you need to rent for everyone to have a place to sit? <span>You would have to rent the 8th table for the remaining 3 people to sit at. </span>

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3 years ago
Stephanie has 60 tickets to the carnival.She used 3/4 of her 60 tickets to play games.Then she used 1/5 of her remaining tickets
Lera25 [3.4K]

Answer:

<h2>She gave her brother 6 tickets</h2>

Step-by-step explanation:

This problem is on fractional numbers.

given that she has 60 tickets

1.She used 3/4 of her tickets to play game

=(3/4)*60

=180/4

=45

She is left with (60-45)= 15 tickets

2. She used 1/5 of her remaining tickets for rides

    =(1/5)*15

   =15/5

   =3

She is left with (15-3)= 12 tickets

3. She gave half of her tickets to her brother.

  = (1/2)*12

  =12/2

 = 6

She gave her brother 6 tickets

3 0
4 years ago
Solve for the exact value of x.
forsale [732]
A² + b² = c²
5² + 8² = x²
x² = 25 + 64
x² = 89
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3 0
3 years ago
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Plz do both plz plz plz
shtirl [24]
The first one is A and the second is either B or D I can’t decide
4 0
3 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
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