We have 3 white balls in the first urn out of 9. That means we have a 1 in 3 chance at picking the white ball in the first urn.
Now, we have a 3 in 11 chance at picking the white ball in the second urn.
Since, we want them simultaneously, we need to multiply them.
1/3 × 3/11 = 1/11 chance
The problem statement tells you "7 friends were playing basketball".
_____
It appears 5 friends were only playing basketball, 2 friends were playing basketball and having snacks, and 3 friends were only having snacks. Apparently, 10 friends were doing neither of those activities.
Answer:
1. $18.75
2.$83.75
3. Individuals should spend up to only %50 of their medium-term savings then build savings back up.
4. Permanent life insurance policies insure policy holders for as long as they pay a premium.
5. She saves $84 (here is the link with the work brainly.com/question/12276113)
Step-by-step explanation:
Just took it and got all the multiple choices right.
have a good day :)
Answer:
7A−(I + A)³
=7A−(1³ + A³ +3.I.A² +3.1².A)
=7A−(I+ A².A+3A² +34)
= 7A-(I+A.A+3A+34) (*: A² = A)
=7A-(I+ A² +6A)
= 7A-(I+A+64)
=7A-(1+7A)
=7A-I-7A
=-1
