Multiply: (1/3sqrtx-3/2sqrty)^2
1 answer:
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Let number of $250 bonus = x
Let number of $750 bonus = 7
Given that total bonus amount awarded is $3000. So we can write equation:
250x+750y=3000
750y=3000-250x
Given that both type of bonus awarded are at least one.
So that means y>1 and x>1
Now we have to find any one possible solution.
Number of awards can only be whole numbers so we can plug x=2,3,4,... to see which one satisfies above equation and gives x as whole number.
I found that x=3 is working good.
at x=3, we get:
y=3
Hence final answer is given by:
Number of $250 bonus = 3
and number of $750 bonus = 3