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UkoKoshka [18]
3 years ago
11

I need help with this question , 13 + 7x = 27

Mathematics
2 answers:
Usimov [2.4K]3 years ago
7 0
13 + 7x = 27
7x=14
x=2

Hope this helps :)
galina1969 [7]3 years ago
3 0

Answer:

x=2

Step-by-step explanation:

27-13=14

14÷7=2

therefore x is equal to 2

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Jobisdone [24]

Step-by-step explanation:

i)=

m=2/3

x=-3

y = 5

now

y=mx+c

or, 5 = 2/3× -3 + c

or, 5 = -2+c

c =7

now,

y= mx + c

or, y = 2/3×x+7

or, y = 2x/3+7

or, 3y = 2x+21

so, 3y-2x=21

equation would be 3y-2x=21.

now

ii)=

if slope of 3y-2x=21 and 2x-3y = 0 are same, they are parallel.

2x-3y = 0

2x = 3y

lets suppose x is 9

now

2x=3y

2×9 = 3y

or, 18 = 3y

so, y = 6

one coordinate would be (9,6) now

lets again suppose x is 3

2x=3y

2×3 = 3y

or, 6 = 3y

so, y = 2

another coordinate is (3,2)

now lets find slope

x1=9,y1=6

x2=3,y2=2

slope = (y2-y1)/(x2-x1)

= (2-6)/(3-9)

= -4/-6

= 2/3

Since, slope of 3y-2x=21 and 2x-3y has same slope 2/3, they are parallel.

6 0
2 years ago
Perform the indicated operation <br> 5(3x^3)^3-2(3x^3)
Pie
<span>5(3x^3)^3-2(3x^3)
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5 0
3 years ago
&lt;ABD has a measure of 36 degrees. a)find the compliment of the angle b)find the supplement of that angle
victus00 [196]
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6 0
3 years ago
Help plz i need it :(
mr_godi [17]

Answer:

B.

C.

D.

E.

Step-by-step explanation:

6 0
3 years ago
The figure here shows triangle AOC inscribed in the region cut from the parabola y=x^2 by the line y=a^2. Find the limit of the
aleksandrvk [35]
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ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =

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</span>
 



3 0
3 years ago
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