Answer:
3x^2
Step-by-step explanation:
d/dx (x^3)
d/dx (x^n) = n*x^(n-1)
3x^2
Both claims are false. In fact,
and
are one the multiplicative inverse of the other. This means, by definition of multiplicative inverse, that
![a \cdot \dfrac{1}{a} = 1 \quad\forall a \in \mathbb{R}](https://tex.z-dn.net/?f=%20a%20%5Ccdot%20%5Cdfrac%7B1%7D%7Ba%7D%20%3D%201%20%5Cquad%5Cforall%20a%20%5Cin%20%5Cmathbb%7BR%7D%20)
So, it doesn't matter if
is positive or negative: the multiplication of one number and its inverse will always be 1: for example,
![(-2) \cdot \dfrac{1}{-2} = \dfrac{-2}{-2} = 1](https://tex.z-dn.net/?f=%20%28-2%29%20%5Ccdot%20%5Cdfrac%7B1%7D%7B-2%7D%20%3D%20%5Cdfrac%7B-2%7D%7B-2%7D%20%3D%201%20)
Similarly, when you multiply two number, the sign of the product depends on the sign of the factors as follows:
So, the multiplication of two negative numbers is a positive number.
Answer:
I think the answer is -25
Step-by-step explanation:
x < - ![\frac{13}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B7%7D)
add
to both sides
- 3x >
+ ![\frac{35}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B35%7D%7B7%7D)
- 3x >
( divide both sides by - 3 )
note that when we divide/ multiply by a negative quantity we must reverse the inequality symbol
x < - ![\frac{13}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B7%7D)
Answer:
![\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B2%7D)
Step-by-step explanation:
the other 3 are perfect squares and have rational answers.
![\sqrt{1.44} =1.2\\\sqrt{1}= 1\\\sqrt{4} =2](https://tex.z-dn.net/?f=%5Csqrt%7B1.44%7D%20%3D1.2%5C%5C%5Csqrt%7B1%7D%3D%201%5C%5C%5Csqrt%7B4%7D%20%3D2)