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Anton [14]
3 years ago
11

What is the area of a square whose diagonal is 14cm

Mathematics
1 answer:
xenn [34]3 years ago
7 0

Answer:

98 cm^{2}

Step-by-step explanation:

The formula for the area of a square when given the diagonal is:

A = \frac{1}{2} d^{2} Where d is the value of the diagonal so it becomes:

0.5 × 14 × 14

This is equal to 98 cm^{2}.

HOPE THIS HELPED

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Answer:

-5.5

Step-by-step explanation:

<em>-10, -9, -8, -8,</em> -6, -5, <em>-1, 1, 7, 6</em>

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3 years ago
Hey guys what's 25 divided by 7 plus 10??
ale4655 [162]
The answer is 13.57
First 25/7 which is 3.57
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11.3d04
alexandr402 [8]

Answer:

yes

Step-by-step explanation: did it on test

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3 years ago
CAN SOMEONE PLEASE HELP ME. ITS HARD AND I CANT SOLVE IT. ILL MARK BRAINLIEST
S_A_V [24]

Answer:

Step-by-step explanation:

Hello,

First of all, we need to find the equation of the line.

It will be something like y = ax + b (we need to find a and b).

Then the graph is the part of the plan which is above this line, so the inequality will be

\large \boxed{\sf  \ \ y\geq ax+b \ \ }

There is only one line passing by two different points, right?

We need to find two points of this line, the x-axis gives the x of the point and the y-axis give the y of the point.

We can see on the graph that (-1,-1) and (6,13) are two points of this line.

I attached a graph with the two points A (-1,-1) and B (6,13).

We need to solve y = ax + b to find a and b which means:

(-1) = a(-1 )+ b <=> -1 = -a + b <=> -a + b = -1

(13) = a(6) + b <=> 6a + b = 13

To eliminate b, we can subtract the first equation from the second one.

6a + b -(-a) - b = 13 - (-1) = 13 + 1 = 14

<=> 6a + a = 7a = 14 we can divide by 7 both parts of the equation.

\large \boxed{\sf \ \ a=\dfrac{14}{7}=2 \ \ }

And then, b = -1 + a = -1 + 2 = 1

\large \boxed{\sf \ \ b=1 \ \ }

The equation of the line is then y=2x+1

So, the inequality is:

\Large \boxed{\sf \ \ y\geq 2x+1 \ \ }

And this is the answer of the question 1.

2. First, we find the equation of the line by finding two points on this line. Then, we deduce the inequality from the equality as the graph is all the points above the line (as explained above).

3. A real-life example is the following.

My parents gave $1 to my sister and they will give her $2 every day.

So today at x = 0 she has $1 and her pocket money will be represented by the line. And I told my parents that there were no way I can get less than my little sister. To help them understand what can be an acceptable deal I provided this graph, and I told them to only look for t positive of course.

The label for the x-axis is the time.

The label for the y-axis is the pocket money in $

After one day x = 1 my sister has $3 (point on the line), a possible solution for my pocket money is $6, $14 (two points from the graph) is also a solution of course :-)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0
4 years ago
Jdjdudhddbbddbdbdbxb
zzz [600]

Answer:

1.6y+y-4/15y+7/6y=21/3

We move all terms to the left:

1.6y+y-4/15y+7/6y-(21/3)=0

Domain of the equation: 15y!=0

y!=0/15

y!=0

y∈R

Domain of the equation: 6y!=0

y!=0/6

y!=0

y∈R

We add all the numbers together, and all the variables

1.6y+y-4/15y+7/6y-7=0

We add all the numbers together, and all the variables

2.6y-4/15y+7/6y-7=0

We calculate fractions

2.6y+(-24y)/90y^2+105y/90y^2-7=0

We multiply all the terms by the denominator

(2.6y)*90y^2+(-24y)+105y-7*90y^2=0

We add all the numbers together, and all the variables

(+2.6y)*90y^2+(-24y)+105y-7*90y^2=0

We add all the numbers together, and all the variables

105y+(+2.6y)*90y^2+(-24y)-7*90y^2=0

Wy multiply elements

-630y^2+105y+(+2.6y)*90y^2+(-24y)=0

We get rid of parentheses

-630y^2+105y+(+2.6y)*90y^2-24y=0

We add all the numbers together, and all the variables

-630y^2+81y+(+2.6y)*90y^2=0

Step-by-step explanation:

5 0
3 years ago
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