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ivolga24 [154]
3 years ago
10

Which statement compares the two numbers correctly?

Mathematics
1 answer:
AVprozaik [17]3 years ago
7 0

Answer:

A

Step-by-step explanation:

Six hundred seventy-two thousandths = 0.672

0.672 < 0.8

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This question means the than (8 + 10) x 2 = red markers. She has 32 red markers, 8 blue markers, and 10 green markers. If you add them all up, you get 50 markers.
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A local company makes a candy that is supposed to weigh 1.00 ounces. A random sample of 25 pieces of candy produces a mean of 0.
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Answer:

n=(\frac{2.58(0.004)}{0.001})^2 =106.50 \approx 107

So the answer for this case would be n=107 rounded up to the nearest integer

Step-by-step explanation:

Information given

\bar X= 0.996 the sample mean

s=0.004 the sample deviation

n =25 the sample size

Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =0.001 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

We can use as estimator of the real population deviation the sample deviation for this case \hat \sigma = s/ The critical value for 99% of confidence interval is given by z_{\alpha/2}=2.58, replacing into formula (b) we got:

n=(\frac{2.58(0.004)}{0.001})^2 =106.50 \approx 107

So the answer for this case would be n=107 rounded up to the nearest integer

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If, P(x,y) is a point on the unit circle determined by real number δ, then tanδ = what
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5 0
3 years ago
Marcy has 150 to buy packages of hotdogs and hamburgers for her booth at the carnival. Grocery store she found packages of hotdo
bekas [8.4K]

Answer:

Part (A): The required equation will be: 6d+20b=150

Part (B):The required equation will be: d=\frac{150-20b}{6}

Part (C):The required equation will be: b=\frac{150-6d}{20}

Step-by-step explanation:

Consider the provided information.

Let d represents number of packages of hot dogs and b represents the number of packages of hamburgers.

Part (a)

It is given that the cost of a package of hot dogs is $6 and cost of a package of hamburger is $20.

The required equation will be: 6d+20b=150

Part (b) Solve the above equation for d.

Subtract 20b from both sides.

6d=150-20b

Divide 6 from both sides.

d=\frac{150-20b}{6}

The required equation will be: d=\frac{150-20b}{6}

Part (c) Solve the equation for b.

Subtract 6d from both sides.

20b=150-6d

Divide 20 from both sides, we get

b=\frac{150-6d}{20}

The required equation will be: b=\frac{150-6d}{20}

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3 years ago
Please help me with this please
Andrew [12]

Answer:

answer iy in the picture...

5 0
3 years ago
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