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3 years ago

Solve the given equation by completing the square.

Mathematics

1 answer:

klasskru [66]3 years ago

3 0

Answer:

Step-by-step explanation:

$x^2+8x=38\\\\x^2+8x-38=0\\\\\Delta=8^2+4*38=216=6^3\\\\x=\dfrac{-8-6\sqrt{6} }{2} \ or\ x=\dfrac{-8+6\sqrt{6} }{2}\\\\x=-4-3\sqrt{6} \ or\ x=-4+3\sqrt{6}\\\\a=-4\\b=3\\c=6\\$

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Justin gave the clerk $20 to pay a bill of $6.57. How much change should Justin get?

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3 0

3 years ago

Are -4 ( x - 6) and -4 • x - 4 • 6 equivalent

tekilochka [14]

Answer:

$no$

Step-by-step explanation:

Lets solve the first half.

$-4 ( x - 6) = -4x + 24$

Second one:

$-4 times x - 4 times 6 = -4x -24$

Now compare.....Not the same right??

So your answer is: $no$

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3 years ago

PLEASE HELP WILL GIVE BRAINLIEST TO CORRECT ANSWER!!

musickatia [10]

Answer:

$p>\frac{1}{14}$

Step-by-step explanation:

Question: $-31p+79>-59p+81$

1) Subtract 79 from both sides:

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2) Add 59p to both sides:

$28p>2$

3) Divide both sides by 28:

$p>\frac{2}{28}$

4) Simplify fraction:

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5 0

3 years ago

The base of a solid in the region bounded by the two parabolas y2 = 8x and x2 = 8y. Cross sections of the solid perpendicular to

Usimov [2.4K]

The two curves intersect at two points, (0, 0) and (8, 8):

$x^2=8y\implies y=\dfrac{x^2}8$

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The area of a semicircle with diameter $d$ is $\dfrac{\pi d^2}8$ . The diameter of each cross-section is determined by the vertical distance between the two curves for any given value of $x$ between 0 and 8. Over this interval, $y^2=8x\implies y=\sqrt{8x}$ and $\sqrt{8x}>\dfrac{x^2}8$ , so the volume of this solid is given by the integral