Question

Solve the given equation by completing the square.

Answer 1

Answer:

Step-by-step explanation:

$x^2+8x=38\\\\x^2+8x-38=0\\\\\Delta=8^2+4*38=216=6^3\\\\x=\dfrac{-8-6\sqrt{6} }{2} \ or\ x=\dfrac{-8+6\sqrt{6} }{2}\\\\x=-4-3\sqrt{6} \ or\ x=-4+3\sqrt{6}\\\\a=-4\\b=3\\c=6$