Question

Find an equation of the line perpendicular to the graph of 14x-7y=4 that passes through the point at (-2,4)

Answer 1

Answer:

y=-0.5x+3

Explanation:

14x-7y=4

7y=14x-4

y=2x-4/7

m1=2

We search for a line y=m2x+b2

m1*m2=-1 (because this line is perpendicular for the line which we have)

So 2m2=-1

m2=-0.5

Then If the point (-2,4) belongs to the searched line  use its coordinates for the line y=m2x+b2

4= (-0.5) (-2)+b2

b2=3

y=-0.5x+3