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irinina [24]
3 years ago
8

How do we find the second and the third derivative of this equation? Please help!

Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0

Answer:

\frac{7}{2\sqrt{2} }

Step-by-step explanation:

substitute 2 in for x. the square root of 2 is already in radical form

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natita [175]

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2.) 10

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6 0
2 years ago
If the measure of angle 1 is (3 x minus 4) degrees and the measure of angle 2 is (4 x + 10) degrees, what is the measure of angl
arlik [135]

Answer:

58 degrees

Step-by-step explanation:

If angle 1 + angle 2 = 90 degrees, then:

(3x - 4) + (4x+10) = 90

Combine like terms:

(3x+4x) + (10-4) = 90

7x + 6 = 90

Subtract 6 from both sides:

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Divide both sides by 7:

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**Plug x back into angle 2 (This step is easy to forget!):

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2 years ago
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Brrunno [24]
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6 0
2 years ago
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Fill in the missing portions of the function to rewrite g(x) = 3a^2 − 42a + 135 to reveal the zeros of the function. What are th
mariarad [96]

Answer:

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

g(x) = 3x^{2} - 42a + 135

So

a = 3, b = -42, c = 135

\bigtriangleup = (-42)^{2} - 4*3*135 = 144

x_{1} = \frac{-(-42) + \sqrt{144}}{2*3} = 9

x_{2} = \frac{-(42) - \sqrt{144}}{2*3} = 5

So

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

8 0
3 years ago
Cos 60 degrees<br> = 1/2<br> and sin 60 degrees<br> = square root 3/2<br> O A. True<br> O B. False
garik1379 [7]

A.

Step-by-step explanation:

sin(60)=

\sqrt{3 |2| }

5 0
2 years ago
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