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Aneli [31]
3 years ago
9

Kelly’s making mom for homecoming she needs a piece of ribbon that is greater than 2/3 of a yard but less than 7/8 of a yard whi

ch length of the ribbon listed below could she use

Mathematics
1 answer:
pshichka [43]3 years ago
3 0
C. 4/5
All you have to do is compare the numbers by making the denominations equal and determining whether or not the fraction is higher or lower than needed.
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Find the area and circumference of a circle with a radius of 4 cm. Use the value 3.14 for pi.
gtnhenbr [62]

Answer:

C= 25.12 cm

Step-by-step explanation:

7 0
3 years ago
Find the length and width of a rectangle that has the given perimeter and a maximum area. perimeter: 28 meters
11Alexandr11 [23.1K]
The perimeter is given by:
 P = 2x + 2y = 28
 The area is given by:
 A = x * y
 Writing the area based on x we have:
 A (x) = x * (14-x)
 Rewriting:
 A (x) = 14x-x ^ 2
 Deriving we have:
 A '(x) = 14-2x
 We equal zero and clear x:
 14-2x = 0
 x = 14/2
 x = 7
 We are now looking for the other dimension:
 y = 14-x
 y = 14-7
 y = 7
 Answer: The length and width of a rectangle that has the given perimeter and a maximum area are:
 
y = 7 meters
3 0
3 years ago
The table shows the ratio of caramel corn to cheddar corn in a bag. What is the constant of proportionality?
Anit [1.1K]

For proportionality constant problems, set up the equation as,

x=Ky,

Where x and y are the two variables you are comparing and <em>K </em>is the proportionality constant. If we take <em>Caramel Corn  </em>values as x and <em>Cheddar Corn </em>values as y, and then solve for <em>K </em>for each ratio lines, we will get the same answer. Let's check.

15=K(10)\\K=\frac{15}{10}= \frac{3}{2},

30=K(20)\\K=\frac{30}{20}= \frac{3}{2}, and

45=K(30)\\K=\frac{45}{30}= \frac{3}{2}.

Hence, the proportionality constant, in this case <em>K,</em> is equal to \frac{3}{2} or 1.5. First answer choice is correct.


ANSWER: 1.5


4 0
3 years ago
Read 2 more answers
Have vehicles gotten more fuel-efficient over the years? Between 1960 and 1999 the size and shape of automobiles in the United S
polet [3.4K]
Answer: option A. 9.2 gal/year

Justification:

The average rate of change from 1960 to 1970 is the change on the variable  gallons consumed per passenger car divided by the period

average rate of change = Δg / Δt

Δg = 760 gallons - 668 gallons

Δt = 1970 year - 1960 year

                                               760 gal - 668 gal              92 gal    
average rate of change =  -------------------------------- = ---------- = 9.2 gal / year
                                             1970 year - 1960 year        10 year

Answer: 9.2 gal / year

As you see for this specific period, 1960 to 1970, the vehicles increased their consumption of gas per passenge, meaning that they became less efficient.
8 0
3 years ago
Read 2 more answers
5. Solve the problem and find the answer
Ghella [55]

Answer:

  x ≈ 263.1

Step-by-step explanation:

The marked sides are the hypotenuse and the side adjacent to the given angle. The relevant trig relation is ...

  Cos = Adjacent/Hypotenuse

  cos(70°) = 90/x . . . . use given values

  x = 90/cos(70°) . . . . multiply by x/cos(70°)

  x ≈ 263.1

_____

<em>Additional comment</em>

The mnemonic SOH CAH TOA is intended to remind you of the primary trig relations:

  Sin = Opposite/Hypotenuse

  Cos = Adjacent/Hypotenuse

  Tan = Opposite/Adjacent

7 0
3 years ago
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