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3 years ago

Identifying equivalent statements and negations of a conditional statement: help

Mathematics

1 answer:

Vitek1552 [10]3 years ago

6 0

Answer:

1: Equal

2: Negation

3: Negation

4: Neither

Step-by-step explanation:

Sorry if I got any of them wrong

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The first 5 terms of a quadratic sequence are

Mashcka [7]

Step-by-step explanation:

an = 2n^2 - 3 · Anonymous. -1, 5, 15, 29, 47, ... an = 2 n^2 - 3.

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3 years ago

What is half of the product of 8 1/7 and 7 4/5

UNO [17]

First we must convert these mixed numbers to improper fractions:

$8\frac{1}{7}=\frac{57}{7}$

$7\frac{4}{5}=\frac{39}{5}$

So then we need the product of these two numbers. That means to multiply:

$\frac{57}{7}* \frac{39}{5}= \frac{2,223}{35}$

But then we need the value of half of this product. So then let's multiply by one-half:

$\frac{2,223}{35} *\frac{1}{2} =\frac{2,223}{70}$

Then we can convert this from an improper fraction to a mixed number:

$\frac{2,223}{70} =31\frac{53}{70}$

And so this number is half of the product of the initial two numbers.

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4 years ago

Use the function below to find f(-4).

Margaret [11]

Answer:

Step-by-step explanation:

f(x) = 2x

f(-4) = 2(-4) = -8

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3 years ago

Perform the indicated operation.(3/a+2) + (4/a-5)

kipiarov [429]

Answer:

$\frac{7(a-1)}{(a+2)(a-5)}$

Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

$\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}$

Thus, the solution is 7(a -1) / (a+2)(a-5)

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3 years ago

A pencil cost $1.20 and a pen cost $2.90. Jasmiah bought an equal number of such pencils and pens. She spent $32.30 more on the

garri49 [273]

Answer:

Step-by-step explanation:

hope it helps good day.

3 0

2 years ago

Read 2 more answers