How do i express x^2-3x into the form of (x-m)^2+n. I will give brainliest to correct answer
1 answer:
Step-by-step explanation:
let's simply do the multiplications and then compare with the original.
(x-m)² + n
right ?
or is it
let's go for the first.
x² - 2mx + m² + n = x² - 3x
-2mx + m² + n = -3x
fun there we see two things :
-2m = -3
m = 3/2
and
m² + n = 0
(3/2)² = -n
9/4 = -n
n = -9/4
so our transformed expression looks like
(x - 3/2)² - 9/4
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Answer:
2, 4
Step-by-step explanation:
Let there are two unknown consecutive pairs of even integers 2n and 2n+2.
If the sum of the reciprocals of those two integers is 3/4, then we can write,
1/2n +1/(2n+2) =3/4 ...... (1)
Solving this above equation we can check whether the integers exist or not.
Now, from equation (1) we get,
1/n +1/(n+1) =3/2
⇒
⇒4n +2 =3n²+3n
⇒3n²-n-2 =0
⇒ (n-1)(3n+2) =0
⇒ (n-1) =0 {Since if (3n+2) =0 then, n will be a negative fraction, which is not possible}
⇒ n=1
∴ 2n =2 and 2n+2 =4
Hence, the two integers are 2, 4. (Answer)