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nikklg [1K]
3 years ago
11

Find the surface area of the

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0

Answer:

169 sq cm

Step-by-step explanation:

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24cd, 9cd unlike or like terms
Schach [20]
They are like terms. They can be added together or one can be subtracted from the other. The exponents of the variables are the same in both terms.<span />
6 0
3 years ago
stephanie and jenny each improved their yards by planting rose bushes and geraniums. they bought their supplies from the same st
galina1969 [7]

Answer:

The cost of one rose is $11., and the cost of one geranium is $5.

Step-by-step explanation:

The cost of one rose bush and one geranium can be determined by the use of simultaneous equation. Let the cost of a rose bush be represented by x, and the cost of one geranium by y.

So that,

13x + y = 148 .............. 1

9x + 14 y = 169 ............... 2

From eqaution 1,

y = 148 - 13x ............... 3

substitute the value of y in equation 2

9x + 14(148 - 13x) = 169

9x + 2072 - 182x = 169

2072 - 169 = 182x - 9x

1903 = 173x

x = \frac{1903}{173}

  = 11

x = 11

substitute the value of x in equation 3

y = 148 - 13x

  = 148 - 13(11)

  = 148 - 143

y = 5

x = 11, y = 5

Thus, the cost of one rose is $11., and the cost of one geranium is $5.

3 0
3 years ago
One more i need help with plz answer I need it done by today
polet [3.4K]

Answer:187.5 inches.

Step-by-step explanation:

25 / 2 = x / 15

25 = 2x / 15

15(25) = 2x

375 = 2x

187.5 = x

The actual car is 187.5 inches.

5 0
3 years ago
Read 2 more answers
Please help me with this!<br> I will give you a thanks!
Grace [21]
-2 + 6
.................
4 0
3 years ago
Read 2 more answers
What is the length of the diameter of a circle inscribed in a right triangle with the length of hypotenuse c and the sum of the
jeyben [28]

Answer:

  diameter = m - c

Step-by-step explanation:

In ΔABC, let ∠C be the right angle. The length of the tangents from point C to the inscribed circle are "r", the radius. Then the lengths of tangents from point A are (b-r), and those from point B have length (a-r).

The sum of the lengths of the tangents from points A and B on side "c" is ...

  (b-r) +(a-r) = c

  (a+b) -2r = c

Now, the problem statement defines the sum of side lengths as ...

  a+b = m

and, of course, the diameter (d) is 2r, so we can rewrite the above equation as ...

  m -d = c

  m - c = d . . . . add d-c

The diameter of the inscribed circle is the difference between the sum of leg lengths and the hypotenuse.

5 0
3 years ago
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