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aivan3 [116]
2 years ago
6

Help !!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
FrozenT [24]2 years ago
5 0

Answer:

xhgfkjfghfhj GIST is the every year and school going to have you a very great night and I will be a hai jismein to the wet weather is very much appreciated the very least I will limited access to the wet please find attached the teeth of the very first to know what I will take a look t e

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The sum of all three numbers is 12. The sum of twice the first number, 4 times the second number, and 5 times the third number i
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The numbers are 7, 4 and 1

Step-by-step explanation:

Let the numbers =x, y, z.

The sum of all three numbers is 12, x+y+z=12--------i

The sum of twice the first number, 4 times the second number, and 5 times the third number is 35, 2x+4y+5z=35-------ii

The difference between 8 times the first number and the second number is 52, 8x-y=52---------iii

Now, from (i),z =1-x-y--------iv

substitute (iv) in (ii),

2x+4y+5(12-x-y)=35

2x+4y+60-5x-5y=35

collect like terms

-3x-y=-25

that is, 3x-y=25--------v

solving (iii) and (v) simultaneously (add iii and v), we have

11x=77

divide both sides by 11 to obtain x=7

Put x=7 in (v)

3(7)+y=25

21+y=25

implies y=25-21=4

put x=7 and y=4 in (iv)

z=12-7-4=1

Hence, the numbers are 7, 4 and 1.

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