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Igoryamba
2 years ago
13

A vehicle is travelling from rest. After 10 seconds its velocity will be 20ms find acceleration?​

Mathematics
1 answer:
Paladinen [302]2 years ago
8 0

Initial velocity (u) = 0m/s

Final velocity (v) = 20m/s

Time (t) = 10 s

Acceleration (a)

= (v - u)/t

= [(20m/s) - (0m/s)]/10s

= (20m/s)/10s

= (20m/s²)/10

=> 2m/s²

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Her hourly rate is <u>$14</u>.

Step-by-step explanation:

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Penelope goes to work after school for 4.5 hours on Mondays, Tuesdays, and Fridays.

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Without exponents<br> logc (xy^6z^-4) what is the equivalent expression
Sever21 [200]

By eliminating exponents, the <em>logarithmic</em> expression \log_{c} x\cdot y^{6}\cdot z^{-4} is equivalent to the <em>logarithmic</em> expression \log_{c} x + 6\cdot \log_{c} y - 4\cdot \log_{c} z.

<h3>How to simplify logarithmic functions</h3>

In this problem we are supposed to eliminate all exponents of a <em>logarithmic</em> function by applying any of the following properties:

  1. ㏒ x · y = ㏒ x + ㏒ y
  2. ㏒ x/y = ㏒ x - ㏒ y
  3. ㏒ yˣ = x · ㏒ y

Now, we proceed to simplify the function:

\log_{c} x\cdot y^{6}\cdot z^{-4}

\log_{c} x + \log_{c} y^{6} + \log_{c} z^{-4}

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By eliminating exponents, the <em>logarithmic</em> expression \log_{c} x\cdot y^{6}\cdot z^{-4} is equivalent to the <em>logarithmic</em> expression \log_{c} x + 6\cdot \log_{c} y - 4\cdot \log_{c} z.

To learn more on logarithms: brainly.com/question/24211708

#SPJ1

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