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Alona [7]
3 years ago
10

What’s 4,708.06 rounded to the nearest thousand?

Mathematics
2 answers:
Andre45 [30]3 years ago
7 0
5000 is the answer. Hope it helps
STALIN [3.7K]3 years ago
3 0

Answer:

when rounding anything that is or is greater than 5 you round up 1.

4,->7<-08.06

so rounding up 1, 4 would turn into 5.

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Choose the ratio that you would use to convert 5.5 pounds to ounces
sdas [7]
We want "pounds" to disappear, in favor of "ounces."

Thus, multiply 5.5 pounds by (16 oz / 1 pound).  "pounds" cancels, leaving you with "88 oz."  
7 0
4 years ago
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Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + sin z j + (x2z + y2)k and S is the top half of
GenaCL600 [577]

Close off the hemisphere S by attaching to it the disk D of radius 3 centered at the origin in the plane z=0. By the divergence theorem, we have

\displaystyle\iint_{S\cup D}\vec F(x,y,z)\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F(x,y,z)\,\mathrm dV

where R is the interior of the joined surfaces S\cup D.

Compute the divergence of \vec F:

\mathrm{div}\vec F(x,y,z)=\dfrac{\partial(xz^2)}{\partial x}+\dfrac{\partial\left(\frac{y^3}3+\sin z\right)}{\partial y}+\dfrac{\partial(x^2z+y^2)}{\partial k}=z^2+y^2+x^2

Compute the integral of the divergence over R. Easily done by converting to cylindrical or spherical coordinates. I'll do the latter:

\begin{cases}x(\rho,\theta,\varphi)=\rho\cos\theta\sin\varphi\\y(\rho,\theta,\varphi)=\rho\sin\theta\sin\varphi\\z(\rho,\theta,\varphi)=\rho\cos\varphi\end{cases}\implies\begin{cases}x^2+y^2+z^2=\rho^2\\\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi\end{cases}

So the volume integral is

\displaystyle\iiint_Rx^2+y^2+z^2\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^3\rho^4\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{486\pi}5

From this we need to subtract the contribution of

\displaystyle\iint_D\vec F(x,y,z)\cdot\mathrm d\vec S

that is, the integral of \vec F over the disk, oriented downward. Since z=0 in D, we have

\vec F(x,y,0)=\dfrac{y^3}3\,\vec\jmath+y^2\,\vec k

Parameterize D by

\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath

where 0\le u\le 3 and 0\le v\le2\pi. Take the normal vector to be

\dfrac{\partial\vec r}{\partial v}\times\dfrac{\partial\vec r}{\partial u}=-u\,\vec k

Then taking the dot product of \vec F with the normal vector gives

\vec F(x(u,v),y(u,v),0)\cdot(-u\,\vec k)=-y(u,v)^2u=-u^3\sin^2v

So the contribution of integrating \vec F over D is

\displaystyle\int_0^{2\pi}\int_0^3-u^3\sin^2v\,\mathrm du\,\mathrm dv=-\frac{81\pi}4

and the value of the integral we want is

(integral of divergence of <em>F</em>) - (integral over <em>D</em>) = integral over <em>S</em>

==>  486π/5 - (-81π/4) = 2349π/20

5 0
3 years ago
∠A and \angle B∠B are supplementary angles. If m\angle A=(2x-16)^{\circ}∠A=(2x−16) ∘ and m\angle B=(5x+28)^{\circ}∠B=(5x+28) ∘ ,
Otrada [13]

Answer:

The measure of angle A is 32

Step-by-step explanation:

A+B=180

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x=24

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6 0
4 years ago
HELPPPPP ASAPPPP!!!!!!
In-s [12.5K]

Hey there!!

Let's take the number as x and y

Given,

The sum of x and y = 12

One number is 2 more than the other

Let's take y = x + 2

Equations

x + y = 12

As we know y = x + 2 , plug the value in

x + x + 2 = 12

2x + 2 = 12

Subtract 2 on both sides

2x = 10

Divide by 5 on both sides

x = 5

y = 2 + x

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Hope my answer helps!

3 0
3 years ago
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If 3220 = 80+7, what is the value of c?
Setler79 [48]

Answer:

Correct option is

C

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So we have, l=30,f0=12,f1=32,f2=20 and h=10

⇒  Mode=l+2f1−f0f2f1−f0×h

                  =30+2×32−12−2032−12×10

                  =30+6.25

                  =36.25

∴  Mode =36.25

8 0
3 years ago
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