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2 years ago

Find the equation of the line that:

Mathematics

1 answer:

Alex Ar [27]2 years ago

7 0

Answer:

Point-Slope: (y - 4) = 3(x - 0)

y=mx + b: y = 3x + 4

Step-by-step explanation:

When a line is parallel, that means that it has a different y-intercept but the same slope.

So, the slope of the new line is the same: 3

<u>Step 1: Use point slope form</u>

(y - y1) = m(x - x1)

(y - 4) = 3(x - 0)

(y - 4) = 3x

<u>Step 2: If needed convert to y = mx + b</u>

y - 4 + 4 = 3x + 4

y = 3x + 4

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Solve the inequality

Mamont248 [21]

32 and Konner is right please

8 0

3 years ago

Tom put 18 gallons of mid grade gas in his truck and filled up his empty five gallon gas tank with regular gas for his lawn mowe

LuckyWell [14K]

Answer:

Mid grade gas per gallon = $2.67

Regular gas per gallon = $2.37

Step-by-step explanation:

Let, x= mid grade gas, y=regular gas.

So, for 18 gallons of mid grade gas and 5 gallon of regular gas at $59.91, it can be expressed as,

$18x+5y=59.91$ ------------------(equation 1)

for 14 gallon of mid grade gas and 1 gallon of regular gas at 39.75, it can be expressed as,

$14x+y=39.75$ -------------------(equation 2)

$y=39.75-14x$ -------------------(equation 3)

Now substituting the value of y from (equation 3) in (equation 1) we get,

$18x+5y=59.91$

$18x+5(39.75-14x)=59.91$

$18x+198.75-70x=59.91$

$52x=198.75-59.91$

$52x=138.84$

$x=\frac{138.84}{52}$

$x=2.67$ -------------------------(equation 4)

Now substituting value of x from (equation 4) in (equation 3) we get,

$y=39.75-14x$

$y=39.75-(14\times2.67)$

$y=39.75-37.38$

$y=2.37$

Therefore price per gallon of mid grade gas is x = $2.67, and price per gallon of regular gas y = $2.37.

4 0

3 years ago

Find the volume of a cylinder with a diameter of 10 inches and height of 20in

weqwewe [10]

Answer:

V = 500 pi in^3

or approximately 1570 in ^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h where r is the radius and h is the height

The diameter is 10. so the radius is d/2 = 10/2 =5

V = pi (5)^2 * 20

V = pi *25*20

V = 500 pi in^3

We can approximate pi by 3.14

V = 3.14 * 500

V = 1570 in ^3

3 0

3 years ago

Read 2 more answers

What is the inverse operation of 2/3x=6

Artemon [7]

2 3 x - 6

Since g(f(x))=x g ( f ( x ) ) = x , f−1(x)=3x2+9 f - 1 ( x ) = 3 x 2 + 9 is the inverse of f(x)=23x−6 f ( x ) = 2 3 x - 6

pls brain

8 0

2 years ago

Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A

iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

$\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA$

7 0

3 years ago