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skad [1K]
3 years ago
7

If tan A= 1,what is the value of A​

Mathematics
1 answer:
xxMikexx [17]3 years ago
6 0

Answer:

45°

Step-by-step explanation:

Ok, so, there is one thing I need to point out. 45° is the 'main' value if you assume 0°<A<180°. However, sin,  cos, and tan have different periods which means that there are infinite values of A where tanA = 1. The general notation that you could put is A = 45° + (n*180°) where n is just a number. For example, if n = 1, you would get an angle of 225°. If you plug tan225° into the calculator, you get 1. If you did radians, you could write A = \frac{\pi}{2} + n\pi. But ignore that if you haven't. Basically, the answer would be 45° if you are assuming A is between 0° and 180°. Also, you could have just used your calculator and types inverse tan function (tan^{-1}) and plug in 1 to find the primary answer of 45.

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Work out the surface area of this sphere.<br> Give your answer to 1 decimal place.
bearhunter [10]

Answer:

452.4

Step-by-step equation:

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7 0
3 years ago
Find the perimeter of a triangle with vertices A(3, 1), B(2, -1), and C(-3, 2). Leave
natulia [17]

The perimeter of triangle is: 14.15 units

Step-by-step explanation:

First of all we have to find the lengths of sides of triangles

Given

A(3, 1), B(2, -1), and C(-3, 2)

The distance formula will be used to find the lengths of sides

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\

So,

AB = \sqrt{(2-3)^2+(-1-1)^2}\\=\sqrt{(-1)^2+(2)^2}\\=\sqrt{1+4}\\=\sqrt{5}\\=2.24\ unitsBC = \sqrt{(-3-2)^2+(2+1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\= 5.83\ units\\AC = \sqrt{(-3-3)^2+(2-1)^2}\\=\sqrt{(-6)^2+(1)^2}\\=\sqrt{36+1}\\=\sqrt{37}\\=6.08\ units

The perimeter of triangle will be:

P = AB+BC+AC\\= 2.24+5.83+6.08\\=14.15\ units

Hence,

The perimeter of triangle is: 14.15 units

Keywords: Triangle Perimeter

Learn more about perimeter at:

  • brainly.com/question/573729
  • brainly.com/question/572693

#LearnwithBrainly

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I got a hold on hood for the
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