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egoroff_w [7]
3 years ago
10

If a:b=5:7 and b:c=6:12, then a:b:c​

Mathematics
1 answer:
uranmaximum [27]3 years ago
3 0

Step-by-step explanation:

A/B=5/7 , B/C=6/12

Taking B=12×7=84, we get

A=12×5=60, C=7×6=42

Hence,

60:84:42. Answer

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What does b equal???​
charle [14.2K]

Answer:

17

Step-by-step explanation:

anddo the work you cheater

5 0
3 years ago
Given g(x)=|-3x+16|, if g(x)=18, find x.
LenaWriter [7]

Answer:

x = - \frac{2}{3} , x = \frac{34}{3}

Step-by-step explanation:

The absolute value function always gives a positive value, however, the expression inside can be positive or negative, that is

- 3x + 16 = 18 or -(- 3x + 16) = 18

Solving

- 3x + 16 = 18 ( subtract 16 from both sides )

- 3x = 2 ( divide both sides by - 3 )

x = - \frac{2}{3}

or

-(- 3x + 16) = 18

3x - 16 = 18 ( add 16 to both sides )

3x = 34 ( divide both sides by 3 )

x = \frac{34}{4}

As a check

Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.

| - 3(- \frac{2}{3} ) + 16 | = | 2 + 16 | = | 18 | = 18 ← True

| - 3(\frac{34}{3} ) + 16 | = | - 34 + 16 | = | - 18 | = 18 ← True

Thus x = - \frac{2}{3} and x = \frac{34}{3} are the solutions

8 0
3 years ago
Read 2 more answers
Solve for x: sinx-cosx=√2
kvv77 [185]
<span>sinx - cosx =sqrt(2)
Taking square on both sides:
</span>(sinx - cosx)^2 =sqrt(2)^2<span>
sin^2(x) -2cos(x)sin(x) + cos^2(x) = 2
Rearranging the equation:
sin^2(x)+cos^2(x) -2cos(x)sin(x)=2
As,
</span><span>sin^2(x)+cos^2(x) = 1
</span><span>So,
1-2sinxcosx=2
 1-1-2sinxcosx=2-1
 -</span><span>2sinxcosx = 1
</span><span>Using Trignometric identities:
-2(0.5(sin(x+x)+sin(x-x))=1 
-sin2x+sin0=1
As,
sin 0 = 0
So,
sin2x+0 = -1
</span><span>sin2x = -1</span><span>
2x=-90 degrees + t360
Dividing by 2 on both sides:
x=-45 degrees + t180
or 2x=270 degrees +t360
x= 135 degrees + t180 where t is integer</span>
6 0
3 years ago
? <br> n0 fake answers please
svp [43]

Answer:

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
(y-8)(y-8)(y-8)<br><br> How do I multiply OR find the special product of this problem ?
photoshop1234 [79]

Answer:

2x^3-23y^2+72-128

Step-by-step explanation:

its like when you just do two

do the first 2 first

(y-8)(y-8)

this is (y^2 -8y+y^2+16) simplify (2x^2-7y+16)

then add the other bracket

(2x^2-7y+16) (y-8)

2x^3-16x^2-7y^2+56y+16y-128 simplify

5 0
3 years ago
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