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dexar [7]
3 years ago
10

Use the points slope formula..

Mathematics
1 answer:
Svetlanka [38]3 years ago
8 0

Answer:

y = -5/14 -13/7

Step-by-step explanation:

First find the slope

m = (y2-y1)/(x2-x1)

m = (1 - -4)/(-8 - 6)

    = (1+4)/(-8-6)

   = 5/-14

   =-5/14

Point slope form is

y-y1 = m(x-x1)

y - -4 = -5/14(x-6)

y+4 = -5/14(x-6)

We want the equation in slope intercept form y = mx+b

Distribute

y+4 = -5/14x + 15/7

Subtract 4 from each side

y+4 -4= -5/14x + 15/7-4

y = -5/14x +15/7 - 28/7

y = -5/14 -13/7

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Answer:

9 - b = ? 9 - 8 = 1 So, your answer is 1.

Step-by-step explanation:

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3 years ago
If you had 38/12 dollars, how much money would that be in dollars and cents (rounded to the nearest penny)?
azamat
$3.17 Just turn the improper fraction into a mixed number which would be 3 1/6. Then, turn THAT into a decimal rounded to the nearest hundredth (pennies) which leads to $3.17.
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pshichka [43]

Answer:

325.26

Step-by-step explanation:

that's the answer because you have to multiply the top

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5 0
3 years ago
There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f
Ann [662]

Answer:

0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647

0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

The estimated population proportion for this case is:

\hat p = \frac{350}{500}=0.7

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647

0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

7 0
3 years ago
(1+v)(v-7) i need help to solve this question
kramer
(1 + v)(v - 7)

1*(v - 7) + v(v - 7)

1*v - 1*7 + v*v - v*7

v - 7 + v² - 7v

v² - 7v + v - 7

 v² - 6v - 7

I hope this helps.
4 0
3 years ago
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