The answer you are looking for is 12.0
First, let's find what m is, the slope of the line...
m= y2-y1/x2-x1
m=7-4/3-2 You end up with 3/1 or 3 as your slope.
so far you have... y=3x+b
<span>Take (2,4). y=mx+b or 4=3*2+b, solving for b: b=4-(3)(2). b=-2.</span>
So your final equation is...
<span>y = 3x-2</span>
Answer:
Step-by-step explanation:
F=(9/5) C +32 has the form of the equation of a straight line: y = mx + b, where m is the slope and b is the y-intercept. By comparing these two equations we see that the slope, m, is (9/5) and the y-intercept is 32 (or (0, 32)).
To graph this, first locate the y-intercept (0, 32); put a dark dot there. Since the slope is 32, or 32/1, move your pencil point 1 unit to the right, from (0, 32) to (1, 32), and then from (1, 32) move y our pencil point 32 units upward. Plot another dark dot there and then draw a straight line through these two points.
We can evaluate the given function F=(9/5) C +32 at C = 15 by replacing C in the formula with 15: F = (9/5)(15) + 32, or F = 59.
The value of c is 
Explanation:
Given that the trinomial is 
We need to determine the value of c such that the trinomial is a perfect square.
The value of c can be determined using the formula,
From the trinomial, the value of b is given by
Substituting the value of b in the above formula, we have,
Squaring both the numerator and denominator, we have,
Thus, the value of c is which makes the trinomial a perfect square.
Answer:
option a)
y = m(0.5) + 1.8
Step-by-step explanation:
Equation
<h3>
y = mx + c</h3>
represent the equation of straight line
here m = gradient of straight line
c = y-intercept
First find the gradient of the graph
<h3>
m = y2 - y1 / x2 - x1</h3>
= 4 - 3 / 4 - 2
= 1 / 2
Put the values in the equation of straight line
y =mx + c
4 = 1/2(4) + c
c = 2
y = 1/2x + 2
which is approximately equal to y = 0.5x + 1.8
