Answer:
UCL (x bar) = 424
LCL (x bar) = 376
Step-by-step explanation:
Given:
Average calories contained, μ = 400
Standard deviation, σ = 30 calories
Sample size, n = 25
a) UCL (x bar) =
On substituting the respective values, we get
UCL (x bar) =
or
UCL (x bar) = 424
Similarly,
LCL (x bar) =
On substituting the respective values, we get
LCL (x bar) =
or
LCL (x bar) = 376
The value of the <em>a, </em>in the provided quadratic equation for which Nancy found one solution as x=1 is 9.
<h3>What is the solution of equation?</h3>The solution of the quadratic equation is the solution of the variable of the equation, for which the equation satisfies.
Nancy found that x=1 is one solution to the quadratic equation. The quadratic equation is,
For this equation, one solution is <em>x</em>=1. Put this value in the above equation to get the value of <em>a,</em>
Thus, the value of the <em>a, </em>in the provided quadratic equation for which Nancy found one solution as x=1 is 9.
Learn more about the solution of the equation here;