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bogdanovich [222]
2 years ago
9

What is 8.22 divided by 6.0 ( in science )

Mathematics
1 answer:
kiruha [24]2 years ago
6 0

Answer:

1.37

Step-by-step explanation:

hope this can help u

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3(x-4) = 2(-2x + 1)<br>this is confusing me​
nata0808 [166]

Answer:

x = 2

Step-by-step explanation:

<em>Distribute</em>

3 (−4) = 2 (−2+1)

3 − 12 = 2 (-2x +1)

<em>Distrubute again</em>

3x - 12 = -4x + 2

<em>Add twelve to both sides of the equation</em>

<em>Simpfly</em>

3x = -4x + 14

<em>Add 4x to both sides of the equation</em>

<em>simpfly</em>

7x = 14

<em>Divide both sides of the equation by the same term</em>

<em>Simpfly</em>

x = 2

5 0
3 years ago
In how many ways can the letters HAPPY be arranged in a row?
ludmilkaskok [199]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
A toy rocket is launched straight up from the top of a building. The function that models the height as a function of time is h(
kicyunya [14]

Answer: 50 ft

Step-by-step explanation:

The correct function is h(t)=-16t^2+200t+50.

Hi, to answer this question we simply have to replace t =0 in the function given:

h(t)=-16t^2+200t+50.

h (0) = -16t^2+200t+50.

h(0) = 50

When the time is 0, the rocket is at the top of the building.

The rocket was launched from a 50 ft height.

Feel free to ask for more if needed or if you did not understand something.  

4 0
3 years ago
Look at the picture<br>​
Sonbull [250]

\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Divide \ both \ sides \ by \ 9. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf  \frac{9(|x-8|)}{9} < \frac{36}{9}   \end{gathered}$}
  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}

<u>                                                                                                                             </u>

         \large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}

<u>                                                                                                                             </u>

           \large\displaystyle\text{$\begin{gathered}\sf x-8 > -4 \ (Condition \ 2) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 > -4+8 \ (Add \ 8 \ to \ both \ \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x > 4 \end{gathered}$}

<u>                                                                                                                             </u>

<u />\underline{\boldsymbol{\sf{Answer}}}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf x < 12 \ and \ x > 4 \end{gathered}$} }

\large\displaystyle\text{$\begin{gathered}\sf Therefore,\bf{\underline{the \  correct \ option}} \  \end{gathered}$}\large\displaystyle\text{$\begin{gathered}\sf is \ \bf{\underline{"A"}}. \end{gathered}$}

6 0
2 years ago
What’s this answer YALL IM STRUGGLING WITH MATH !!
saul85 [17]

Area: 4900

Perimeter: 280

5 0
2 years ago
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