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Fantom [35]
3 years ago
5

In the town of Rockville, 35 of the students in middle school participate in organized sports after school. If 14 of them play b

asketball, what fraction of the students play basketball?
Mathematics
1 answer:
krek1111 [17]3 years ago
5 0

Answer:

2/5

Step-by-step explanation:

The fraction that play basketball is the number that play basketball over the total

14/35

Divide the top and bottom by 7

2/5

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0, 7, 14, 21, next three terms
Nat2105 [25]

Answer:

28, 35, 42

Step-by-step explanation:

Adding by 7 every time. Also this is on the seven times table.

5 0
3 years ago
Maggie is standing in her front yard and measures the length of the shadow she casts, as well as the shadow, cast by her house.
zimovet [89]

Answer:

the answer is 57

Step-by-step explanation:

because you round to the nearest foot which it means that the answer good luck hope this helps

3 0
3 years ago
Help please! absolute value equations! ​
Bas_tet [7]

Answer:

n = -1                       n = -7

Step-by-step explanation:

5| 2n+8| +3 = 33

Subtract 3 from each side

5| 2n+8| +3-3 = 33-3

5| 2n+8| = 30

Divide by 5

5/5| 2n+8| = 30/5

| 2n+8| = 6

An absolute value equation has two solutions, one positive and one negative

2n+8 = 6              2n+8 = -6

Subtract 8 from each side

2n+8-8=6-8          2n+8-8 = -6-8

2n = -2                    2n = -14

Divide by 2

2n/2 = -2/2            2n/2 = -14/2

n = -1                       n = -7

3 0
3 years ago
Consider the work shown for 94÷3. What does 31 represent?
alina1380 [7]
I think it represents the answer to the problem.
6 0
3 years ago
Read 2 more answers
A sample of 25 undergraduates reported the following dollar amounts of entertainment expenses last year:
marin [14]

Answer:

Range = 85

\sigma = 28.71

Interval = [666.78, 781.62]

Step-by-step explanation:

Given

The data for 25 undergraduates

Solving (a): Range and Standard deviation

The range is:

Range = Highest - Least

From the dataset:

Highest = 772

Least = 687

So:

Range = Highest - Least

Range = 772-687

Range = 85

The standard deviation is:

\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}

First, calculate the mean

\bar x = \frac{769 +691 +............+715}{25}

\bar x = \frac{18105}{25}

\bar x = 724.2

So, the standard deviation is:

\sigma = \sqrt{\frac{(769-724.2)^2 +(691-724.2)^2 +(699-724.2)^2 +(730-724.2)^2 +............+(715-724.2)^2}{25}}

\sigma = \sqrt{\frac{20604}{25}}

\sigma = \sqrt{824.16}

\sigma = 28.71

Solving (b): The interval of the 95% of the observation.

Using the emperical rule, we have:

Interval = [\bar x - 2*\sigma, \bar x+ 2*\sigma]

Interval = [724.2 - 2*28.71, 724.2 + 2*28.71]

Interval = [666.78, 781.62]

4 0
3 years ago
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