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Maru [420]
3 years ago
15

Prove bn=dn..........​

Mathematics
1 answer:
raketka [301]3 years ago
3 0

Answer:

See Below.

Step-by-step explanation:

We can write a two-column proof.

<u>Statements:</u>                                                          <u>Reasons:</u>

<u />\displaystyle 1) \text{ } N \text{ is the midpoint of } \overline{AE}                                  Given

\displaystyle 2) \text{ } \angle 1 \cong \angle 2                                                            Given

\displaystyle 3) \text{ } \angle A \cong \angle E                                                          Given

\displaystyle 4) \text{ } \overline{AN} \cong \overline{NE}                                                        Definition of Midpoint

\displaystyle 5) \text{ } \Delta ABN \cong \Delta EDN                                             ASA Congruence

\displaystyle 6) \text{ } \overline{BN} \cong \overline{DN}                                                       CPCTC              

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The mean salary of actuaries is LaTeX: \mu=\$100,000????=$100,000 and the standard deviation is LaTeX: \sigma=\$36,730????=$36,7
krek1111 [17]

Answer:

The lower limit of 95% confidence interval is 99002.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $100,000

Sample mean, \bar{x} = $111,000

Sample size, n = 36

Alpha, α = 0.05

Population standard deviation, σ = $36,730

First, we design the null and the alternate hypothesis

H_{0}: \mu = \$100,000\\H_A: \mu \neq \$100,000

We have to find the lower limit of the 95% confidence interval.

95% Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

111000 \pm 1.96(\dfrac{36730}{\sqrt{36}} )\\\\ = 111000 \pm 11998.4667 \\= (99001.5333,122998.4667)\\ \approx (99002,122999)

The lower limit of 95% confidence interval is 99002.

6 0
4 years ago
The data shows the weights of 2 groups of house cats in pounds.
lesantik [10]
I would say the answer is C
5 0
3 years ago
Given f (x)=2x-5x-3 and g (x)=2x^2+x what is (f/g)(x)<br>​
Rufina [12.5K]

ANSWER

( \frac{f}{g} )(x ) =   \frac{x - 3}{x}  \: where \:  \: x \ne0, -  \frac{1}{2}

EXPLANATION

Given:

f(x) = 2 {x}^{2}  - 5x - 3

and

g(x) = 2 {x}^{2}  + x

Then,

( \frac{f}{g} )(x ) =  \frac{f(x)}{g(x)}

Substitute the given functions;

( \frac{f}{g} )(x )  =  \frac{2 {x}^{2} - 5x - 3}{2 {x}^{2}  + x}

Factor

( \frac{f}{g} )(x ) =  \frac{2 {x}^{2} - 6x + x - 3 }{x(2x + 1)}

( \frac{f}{g} )(x ) =   \frac{2x(x - 3) +1 (x - 3)}{x(2x + 1)}

( \frac{f}{g} )(x ) =   \frac{(2x + 1)(x - 3) }{x(2x + 1)}

Cancel the common factors.

( \frac{f}{g} )(x ) =   \frac{x - 3}{x}  \: where \:  \: x \ne0, -  \frac{1}{2}

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3 years ago
Does anyone know at this means:
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Let's say x = 16.  In the equation 4 + x(3/x) then you use 16 instead of x.  So it would look like 4 + 16(16/3).  4 plus 16 times 16 divided by 3.
4 0
3 years ago
Explain why 80% of dentists use toothpaste is misleading
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It doesn't specify
"and based of what"
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